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anonymous
 5 years ago
how do you solve
2+4x+x square=0
and getting the answers 0.59, 3.41
anonymous
 5 years ago
how do you solve 2+4x+x square=0 and getting the answers 0.59, 3.41

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0combine like terms: 2 +4x +x = 0.....x square?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x^2 + 4x + 2 = 0 2 + sqrt(2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes x square i dont know how to write the little two on the top

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the 6 button has a caret if your shift it :) x^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok.. so how do i get the answers 0.59 and 3.41 by doing this equation???

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[x^2+4x+2=0\] is a quadratic equation ( a polynomial of second degree).. The discriminant is \[Δ=4^24*1*2=8\] so the roots are \[x_1=(4+\sqrt{Δ})/(2*1)=0.59\] and \[x_2=(4\sqrt{Δ})/(2*1)=3.41\] For more information try: http://en.wikipedia.org/wiki/Quadratic_equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I should add that when you have a quadratic equation \[ax^2+bx+c=0\] the discriminant is \[Δ=b^24ac\] and the roots are \[x1=(b+\sqrt{Δ})/2a\] and \[x2=(b\sqrt{Δ})/2a\]
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