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anonymous

  • 5 years ago

how do you solve 2+4x+x square=0 and getting the answers -0.59, -3.41

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  1. amistre64
    • 5 years ago
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    combine like terms: 2 +4x +x = 0.....x square?

  2. amistre64
    • 5 years ago
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    x^2 + 4x + 2 = 0 -2 +- sqrt(2)

  3. anonymous
    • 5 years ago
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    yes x square i dont know how to write the little two on the top

  4. amistre64
    • 5 years ago
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    the 6 button has a caret if your shift it :) x^2

  5. anonymous
    • 5 years ago
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    ok.. so how do i get the answers -0.59 and -3.41 by doing this equation???

  6. anonymous
    • 5 years ago
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    \[x^2+4x+2=0\] is a quadratic equation ( a polynomial of second degree).. The discriminant is \[Δ=4^2-4*1*2=8\] so the roots are \[x_1=(-4+\sqrt{Δ})/(2*1)=-0.59\] and \[x_2=(-4-\sqrt{Δ})/(2*1)=-3.41\] For more information try: http://en.wikipedia.org/wiki/Quadratic_equation

  7. anonymous
    • 5 years ago
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    I should add that when you have a quadratic equation \[ax^2+bx+c=0\] the discriminant is \[Δ=b^2-4ac\] and the roots are \[x1=(-b+\sqrt{Δ})/2a\] and \[x2=(-b-\sqrt{Δ})/2a\]

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