The population P in 1997 for a state is given along with r, it's annual percentage of continuous growth.
P=33 millions, r=1.7%
(a) Write the formula f(x) =P erx, where r is in decimal notation, that model the population in millions x years after 1997
(b)Estimate the population in 2015

- anonymous

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- amistre64

r = .017

- amistre64

33,000,000 e^(.017*1000000(x))

- anonymous

........

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## More answers

- anonymous

33? Wth?

- anonymous

Newton?

- anonymous

33 million is written out there.

- anonymous

that doesnt make sense

- anonymous

The formula says Perx which is usually just an abbreviation for f(x)=Pe^(rx)

- amistre64

its your question, not mine ;) im just the messenger....of doom!!

- amistre64

do we have to use millions of years to find 2015?

- anonymous

Dude, I have no clue, lol. That doesn;t make sense.

- amistre64

why dont it make sense?

- amistre64

large numbers are allowed to exist ;)

- amistre64

or maybe it means:
Write the formula f(x) =P erx, where r is in decimal notation, that model the population (in millions); x years after 1997

- amistre64

33,000,000 e^(.017x)

- amistre64

33 e^(.017x) seems more reasonable then.... if I parse the question correctly

- amistre64

x = 18...(2015)
33 * (e^(.017 * 18)) = 44.8134161 million

- anonymous

it wasn;t right....... :(

- amistre64

which one, the 33 e^(.017x) ? cause that seems to be the most logical one

- anonymous

correct answer was...........

- anonymous

33e^0.017x

- anonymous

33 million wasn't correct either
ARGHH!

- amistre64

:) whats the correct answer then

- anonymous

44.8

- anonymous

Ready for same problem, new numbers?

- amistre64

I got that for b already

- anonymous

you said 33 mil

- amistre64

no, I said 33 million was how you set the problem up; not the answer; you gave a 2 parter. :)

- anonymous

:(

- amistre64

part 1: set up an equation to use with this info: 33 e^(.017x)
part 2) use it to find the population in 18 years

- amistre64

33 million was part of the setup; in part 1.

- anonymous

The population P in 1991 for a state is given along with r, it's annual percentage of continuous growth.
P=34 millions, r=2.3%
(a) Write the formula f(x) =P erx, where r is in decimal notation, that model the population in millions x years after 1991
(b)Estimate the population in 2016

- amistre64

PART A :) 34 e^(.023x)
PART B ;)
2016-1991 = 25
34 * (e^(.023 * 25)) = 60.4224379

- anonymous

that wasn't it! nooooooooooo

- anonymous

I'm shocked!

- amistre64

that should be it unless google lied to me in the math..

- anonymous

That formula should be correct?

- amistre64

60.4224379.... is the same answer I get on the calculator

- amistre64

I used the formula they gave you and the numbers.... there isnt really a way to mess that up :) even for me...

- amistre64

60.4 maybe is what they want

- anonymous

I was trying the formula first the .......34 e^(.023x)

- anonymous

for A

- amistre64

i dont know how they want it formated; thats a computer program issue, but the formula itself is good

- anonymous

aw nuts.

- anonymous

it was 0.023

- amistre64

....those bastards!.... they killed kenny

- anonymous

second part was right! ;)

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