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anonymous
 5 years ago
The population P in 1997 for a state is given along with r, it's annual percentage of continuous growth.
P=33 millions, r=1.7%
(a) Write the formula f(x) =P erx, where r is in decimal notation, that model the population in millions x years after 1997
(b)Estimate the population in 2015
anonymous
 5 years ago
The population P in 1997 for a state is given along with r, it's annual percentage of continuous growth. P=33 millions, r=1.7% (a) Write the formula f(x) =P erx, where r is in decimal notation, that model the population in millions x years after 1997 (b)Estimate the population in 2015

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.133,000,000 e^(.017*1000000(x))

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.033 million is written out there.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that doesnt make sense

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The formula says Perx which is usually just an abbreviation for f(x)=Pe^(rx)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1its your question, not mine ;) im just the messenger....of doom!!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1do we have to use millions of years to find 2015?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Dude, I have no clue, lol. That doesn;t make sense.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1why dont it make sense?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1large numbers are allowed to exist ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1or maybe it means: Write the formula f(x) =P erx, where r is in decimal notation, that model the population (in millions); x years after 1997

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.133 e^(.017x) seems more reasonable then.... if I parse the question correctly

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1x = 18...(2015) 33 * (e^(.017 * 18)) = 44.8134161 million

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it wasn;t right....... :(

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1which one, the 33 e^(.017x) ? cause that seems to be the most logical one

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0correct answer was...........

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.033 million wasn't correct either ARGHH!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1:) whats the correct answer then

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ready for same problem, new numbers?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1I got that for b already

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1no, I said 33 million was how you set the problem up; not the answer; you gave a 2 parter. :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1part 1: set up an equation to use with this info: 33 e^(.017x) part 2) use it to find the population in 18 years

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.133 million was part of the setup; in part 1.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The population P in 1991 for a state is given along with r, it's annual percentage of continuous growth. P=34 millions, r=2.3% (a) Write the formula f(x) =P erx, where r is in decimal notation, that model the population in millions x years after 1991 (b)Estimate the population in 2016

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1PART A :) 34 e^(.023x) PART B ;) 20161991 = 25 34 * (e^(.023 * 25)) = 60.4224379

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that wasn't it! nooooooooooo

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1that should be it unless google lied to me in the math..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That formula should be correct?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.160.4224379.... is the same answer I get on the calculator

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1I used the formula they gave you and the numbers.... there isnt really a way to mess that up :) even for me...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.160.4 maybe is what they want

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I was trying the formula first the .......34 e^(.023x)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1i dont know how they want it formated; thats a computer program issue, but the formula itself is good

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1....those bastards!.... they killed kenny

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0second part was right! ;)
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