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anonymous
 5 years ago
For what values of t the interval [0,2π] is sin t = √3/2? And explain how to figure out the answer please :)
anonymous
 5 years ago
For what values of t the interval [0,2π] is sin t = √3/2? And explain how to figure out the answer please :)

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0draw a unit circle; and the basic trig stuff that they taught you to do lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0at 60 and 120 degrees. Remember the SOH CAH TOA thing, and memorize the 45 45 90 and 30 60 90 triangle and you're set

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0btw, if you don't know it, it goes Sin=Opposite/Hypotenuse Cos=Adjacent/Hypotenuse Tangent=Opposite/Adjacent

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the only way to prove that sin 60 = sqrt(3)/2 is to draw an equilateral triangle, split it in half and pythag it

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0then rotate your angle along the unit cirlce thru the quadrants and see which ones are +

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Dur just basic trig. thanks :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so, certain angles have exact values as you go from 0 to 2 pi. these are 30= pi/6 , 45= pi/4 and 60= pi/3. every angle similar to it is found by adding or subtracting those values from or to pi or 2 pi. This is called the unit circle, where x = cos of an angle, y= sin of the angle. the sin of pi/3 = sqrt(3)/2 and the cos = (1/2), the cos of pi/6 = sqrt(3) and the sin = 1/2. It is more of a memorization type of thing for thes critical values and how they change. You can find each individual one by drawing a circle with a radius = 1 then using the pythagorean theorem to solve for the trig ratios.
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