## anonymous 5 years ago 3nth sqrt 50x^2z^5 X 3nth sqrt 15y^3

1. anonymous

In this case, it's not so nice because you don't have things you can easily divide. But fractional exponents are valid notationally

2. anonymous

So $\sqrt[3]{a^2} = a^{\frac{2}{3}}$

3. anonymous

well idk if this is right but i got 5sqrt 6yz^2

4. anonymous

Wait, the original expression you have is $\sqrt[3]{50x^2z^5} \times \sqrt[3]{15y^3}$ ?

5. anonymous

yeah. because i broke 50 into radical 25 and and 2

6. anonymous

Ok, so yes. If you bring the insides of both together you can factor out a 5 and a z.

7. anonymous

So the only problem is that you should have a y and a z on the outside as well.

8. anonymous

$\sqrt[3]{50*15x^2y^3z^5} = \sqrt[3]{6*5^3x^2y^3z^3z^2}$ And we take out everything with a power of 3. $= 5yz*\sqrt[3]{6x^2z^2}$

9. anonymous

ohh. okaiee. that makes sense. thanks once again

10. anonymous

All of this is just remembering your rules for exponents when you multiply or raise to a power. a $a^b*a^c = a^{b+c}$ $(a^b)^c = a^{b*c}$