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anonymous
 5 years ago
find if limit exists: lim(x,y)>(0,0) [6(x^3)y]/[2(x^4) + (y^4)]
anonymous
 5 years ago
find if limit exists: lim(x,y)>(0,0) [6(x^3)y]/[2(x^4) + (y^4)]

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0openstudy website changes\

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hold one of the variables constant, for example (x,0) >(0,0) lim 0/2x^4. It suggests the limit is 0. This is the answer your instructor is looking for (although it doesn't necessarily prove it; it requires more rigorous work to prove it.) Knowing that info, you can say the limit is zero.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think there is another answer maybe? b/c it doesn't matter whether you put x = 0 or y = 0 it will equal 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That strengthens the argument the lim is zero. There are infinitely many ways to approach the (0,0) and you have established at least two of them. If the answers were different it would prove that the limit does not exist.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay thanks. i thought i was supposed to munipulate the equation and find that the limit doesn't exists.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It is an open question: may be it exists may be not. The interesting about this is it is not continuous (x,y) can not be 0. However, you can still find the lim because you are studying it as it gets closer and closer to 0 even though it doesn't get there. (In this case, the equation can not be manipulated further.)
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