Verify the solution of the differential equation...y=C_1*cos(x)+C_2*sin(x) y''=+y=0

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Verify the solution of the differential equation...y=C_1*cos(x)+C_2*sin(x) y''=+y=0

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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It just wants you to take the derivative twice and see that the second derivative of the function is the function itself.
Did you take the derivative of y with respect to x yet?
I don't understand how to take the derivative twice 'cause i don't know what the C_1 and C_2 mean..are they just constants? so I could replace them with a and b?

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Yes, they are constants. You can use anything you like for those
:D thanks :) I got it :)
great! =)

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