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anonymous

  • 5 years ago

i need help solving this system by graphing??..

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  1. anonymous
    • 5 years ago
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    \[\left\{ 2x+y=-7 \right\} \]

  2. anonymous
    • 5 years ago
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    y=2x-7

  3. anonymous
    • 5 years ago
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    \[\left\{ -3x+2y=14 \right\}\]

  4. anonymous
    • 5 years ago
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    {−3x+2y=14} -2y -2y -3x=12 /-3 /-3 x=-4

  5. anonymous
    • 5 years ago
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    \[\{\begin{matrix}2x + y = -7 \\ -3x+2y = 14\end{matrix}\}\]

  6. anonymous
    • 5 years ago
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    ok i got through the first step

  7. anonymous
    • 5 years ago
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    To solve by graphing, rewrite them in the standard y=mx + b form and graph each one. Then find where they cross.

  8. anonymous
    • 5 years ago
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    wait, im confused??

  9. anonymous
    • 5 years ago
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    2x+y=−7} in y=mx+b for its like this y=2x-7

  10. anonymous
    • 5 years ago
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    i plug in the other equation into y=mx+b

  11. anonymous
    • 5 years ago
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    If you are asked to solve by graphing you have to write the equations in standard form and graph them.

  12. anonymous
    • 5 years ago
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    yess

  13. anonymous
    • 5 years ago
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    yes

  14. anonymous
    • 5 years ago
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    so now i jst do this

  15. anonymous
    • 5 years ago
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    y=2(-4)-7

  16. anonymous
    • 5 years ago
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    y=-8-7

  17. anonymous
    • 5 years ago
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    \[2x + y = -7 \implies y = -2x + -7\] So draw that line on some graph paper. \[-3x+ 2y = 14 \implies y = \frac{3}{2}x + 7\]

  18. anonymous
    • 5 years ago
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    ???

  19. anonymous
    • 5 years ago
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    You don't do any algebra when you solve by graphing.

  20. anonymous
    • 5 years ago
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    then hyou make a table of values then you get your coordinates and graph them on the graph and when it makes a straight line you draw it throughth and make sure you xtende the line

  21. anonymous
    • 5 years ago
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    (Other than the algebra to get the equation into standard form)

  22. anonymous
    • 5 years ago
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    wait so how do i get the corrdinates?

  23. anonymous
    • 5 years ago
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    by using numbers for x and psubititing it to the equation and you get you x and y then you graph them

  24. anonymous
    • 5 years ago
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    yes i already have some graphed because i have a multiple choice.

  25. anonymous
    • 5 years ago
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    ok

  26. anonymous
    • 5 years ago
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    if you needl help ask me

  27. anonymous
    • 5 years ago
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    yes i do

  28. anonymous
    • 5 years ago
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    ok

  29. anonymous
    • 5 years ago
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    i dnt noe how to get the y value?

  30. anonymous
    • 5 years ago
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    ok what is your first eqution

  31. anonymous
    • 5 years ago
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    do i jst plug it into the equation

  32. anonymous
    • 5 years ago
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    whats the equation

  33. anonymous
    • 5 years ago
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    2x+y=-7

  34. anonymous
    • 5 years ago
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    Just plot 2 points and draw a straight line that goes through each of them.

  35. anonymous
    • 5 years ago
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    Set x=0 for the first point and figure out what y is. Then set y = 0 for the second point and find what x is.

  36. anonymous
    • 5 years ago
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    polpak i tryed that its doesnt help

  37. anonymous
    • 5 years ago
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    either way i dnt need to graph them they r alrdy graphed

  38. anonymous
    • 5 years ago
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    ok good

  39. anonymous
    • 5 years ago
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    Oh, then just check to see which ones go through the points you plot.

  40. anonymous
    • 5 years ago
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    ok i will check.

  41. anonymous
    • 5 years ago
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    but do you get how to get x an y

  42. anonymous
    • 5 years ago
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    no i dnt

  43. anonymous
    • 5 years ago
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    yoplak you mean at which oints do they intersect

  44. anonymous
    • 5 years ago
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    i tried to check on the graph and didnt understand

  45. anonymous
    • 5 years ago
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    so ok diid you changed the equation they give you to y=mx+b form

  46. anonymous
    • 5 years ago
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    yes

  47. anonymous
    • 5 years ago
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    y=2x-7

  48. anonymous
    • 5 years ago
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    what are the equations that you changed

  49. anonymous
    • 5 years ago
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    the top one which is 2x+y=-7

  50. anonymous
    • 5 years ago
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    ok

  51. anonymous
    • 5 years ago
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    so do i jst plug in the x value that i got

  52. anonymous
    • 5 years ago
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    which was -4?

  53. anonymous
    • 5 years ago
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    can you attach this work and give me the linnk

  54. anonymous
    • 5 years ago
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    how?

  55. anonymous
    • 5 years ago
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    what numbers diid you use for x

  56. anonymous
    • 5 years ago
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    ask one of your parents

  57. anonymous
    • 5 years ago
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    ohh the choices u mean??

  58. anonymous
    • 5 years ago
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    ok

  59. anonymous
    • 5 years ago
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    a.(-4,-1) b.(-4,1) c.(4,1) d.(4,-1)

  60. anonymous
    • 5 years ago
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    i think its either a or b.

  61. anonymous
    • 5 years ago
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    wht is the questiom

  62. anonymous
    • 5 years ago
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    solve the system by graphing

  63. anonymous
    • 5 years ago
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    ok diid you grpah the equatios

  64. anonymous
    • 5 years ago
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    noo they r alrdy graphed they r the choices too withthe x and y values

  65. anonymous
    • 5 years ago
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    what doe the graph show does it show 2 lines crossing each other

  66. anonymous
    • 5 years ago
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    yes

  67. anonymous
    • 5 years ago
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    at what point do they intersect

  68. anonymous
    • 5 years ago
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    in other words cross at which 2 points

  69. anonymous
    • 5 years ago
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    which one??

  70. anonymous
    • 5 years ago
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    a is 0 n 6 i think

  71. anonymous
    • 5 years ago
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    both of the lines

  72. anonymous
    • 5 years ago
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    how do i knoe they r like in the middle of 2 #s?

  73. anonymous
    • 5 years ago
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    can you make an attachmen t to this work so i can see this

  74. anonymous
    • 5 years ago
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    ask your mom or dad

  75. anonymous
    • 5 years ago
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    so i can help you better and faster

  76. anonymous
    • 5 years ago
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    i wuld have to scan it to the comp.

  77. anonymous
    • 5 years ago
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    yes

  78. anonymous
    • 5 years ago
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    ill see wait a lil

  79. anonymous
    • 5 years ago
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    ok

  80. anonymous
    • 5 years ago
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    u there

  81. anonymous
    • 5 years ago
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    yes

  82. anonymous
    • 5 years ago
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    diid you scan it

  83. anonymous
    • 5 years ago
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    im doing it rite now

  84. anonymous
    • 5 years ago
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    ok

  85. anonymous
    • 5 years ago
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    what grade you in

  86. anonymous
    • 5 years ago
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    8th and u??

  87. anonymous
    • 5 years ago
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    me too

  88. anonymous
    • 5 years ago
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    ohh

  89. anonymous
    • 5 years ago
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    am good at math i diid this already

  90. anonymous
    • 5 years ago
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    i knew it your were in 8th

  91. anonymous
    • 5 years ago
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    ohh im not so good

  92. anonymous
    • 5 years ago
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    are you finsih scaning

  93. anonymous
    • 5 years ago
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    ok its saving

  94. anonymous
    • 5 years ago
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    ok give me the link

  95. anonymous
    • 5 years ago
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    i cant find it

  96. anonymous
    • 5 years ago
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    wait a lil plz

  97. anonymous
    • 5 years ago
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    ok

  98. anonymous
    • 5 years ago
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    ohh it look all weird

  99. anonymous
    • 5 years ago
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    how

  100. anonymous
    • 5 years ago
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    1 Attachment
  101. anonymous
    • 5 years ago
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    let me scan it again

  102. anonymous
    • 5 years ago
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    you made it uupside down

  103. anonymous
    • 5 years ago
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    yea i noe im scanning it again.

  104. anonymous
    • 5 years ago
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    ok how many questions you have got i can help you

  105. anonymous
    • 5 years ago
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    quite a feww.

  106. anonymous
    • 5 years ago
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    ok am happy to help

  107. anonymous
    • 5 years ago
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    are you doing scanning

  108. anonymous
    • 5 years ago
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    yes

  109. anonymous
    • 5 years ago
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    ok

  110. anonymous
    • 5 years ago
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    plz give me the link

  111. anonymous
    • 5 years ago
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    1 Attachment
  112. anonymous
    • 5 years ago
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    ohh sry i gave u the wrong one

  113. anonymous
    • 5 years ago
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    ok it wont open though

  114. anonymous
    • 5 years ago
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    1 Attachment
  115. anonymous
    • 5 years ago
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    ohh that was the other side let me do it one more time srry.

  116. anonymous
    • 5 years ago
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    make it clear becuse it hard to understand the questions

  117. anonymous
    • 5 years ago
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  118. anonymous
    • 5 years ago
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    i cant see th egprah for question 3 it confusing its dark

  119. anonymous
    • 5 years ago
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    i noe thats the best ican get it too

  120. anonymous
    • 5 years ago
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    ok so why are the graphs colored

  121. anonymous
    • 5 years ago
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    idkk

  122. anonymous
    • 5 years ago
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    because on my paper they r shaded with like gray n black

  123. anonymous
    • 5 years ago
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    why though

  124. anonymous
    • 5 years ago
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    because thats how they r

  125. anonymous
    • 5 years ago
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    heyy r u still there??

  126. anonymous
    • 5 years ago
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    yes

  127. anonymous
    • 5 years ago
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    ok

  128. anonymous
    • 5 years ago
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    whicc question you working on

  129. anonymous
    • 5 years ago
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    4.

  130. anonymous
    • 5 years ago
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    its a -4,-1

  131. anonymous
    • 5 years ago
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    how do u noe?

  132. anonymous
    • 5 years ago
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    jst tell me how u got -1?

  133. anonymous
    • 5 years ago
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    ok if you plugg -4 for bopth equations for x you r x will be -4 and y -1 for both equations

  134. anonymous
    • 5 years ago
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    i pluged it in and got this

  135. anonymous
    • 5 years ago
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    y=2(-4)-7

  136. anonymous
    • 5 years ago
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    y=-8-7

  137. anonymous
    • 5 years ago
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    which equals 15 ???

  138. anonymous
    • 5 years ago
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    ???

  139. anonymous
    • 5 years ago
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    heyy

  140. anonymous
    • 5 years ago
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    r u still there???

  141. anonymous
    • 5 years ago
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    hey

  142. anonymous
    • 5 years ago
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    yeah

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