i need help solving this system by graphing??..

- anonymous

i need help solving this system by graphing??..

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- anonymous

\[\left\{ 2x+y=-7 \right\} \]

- anonymous

y=2x-7

- anonymous

\[\left\{ -3x+2y=14 \right\}\]

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## More answers

- anonymous

{−3x+2y=14}
-2y -2y
-3x=12
/-3 /-3
x=-4

- anonymous

\[\{\begin{matrix}2x + y = -7 \\ -3x+2y = 14\end{matrix}\}\]

- anonymous

ok i got through the first step

- anonymous

To solve by graphing, rewrite them in the standard y=mx + b form and graph each one. Then find where they cross.

- anonymous

wait, im confused??

- anonymous

2x+y=−7} in y=mx+b for its like this y=2x-7

- anonymous

i plug in the other equation into y=mx+b

- anonymous

If you are asked to solve by graphing you have to write the equations in standard form and graph them.

- anonymous

yess

- anonymous

yes

- anonymous

so now i jst do this

- anonymous

y=2(-4)-7

- anonymous

y=-8-7

- anonymous

\[2x + y = -7 \implies y = -2x + -7\]
So draw that line on some graph paper.
\[-3x+ 2y = 14 \implies y = \frac{3}{2}x + 7\]

- anonymous

???

- anonymous

You don't do any algebra when you solve by graphing.

- anonymous

then hyou make a table of values then you get your coordinates and graph them on the graph and when it makes a straight line you draw it throughth and make sure you xtende the line

- anonymous

(Other than the algebra to get the equation into standard form)

- anonymous

wait so how do i get the corrdinates?

- anonymous

by using numbers for x and psubititing it to the equation and you get you x and y then you graph them

- anonymous

yes i already have some graphed because i have a multiple choice.

- anonymous

ok

- anonymous

if you needl help ask me

- anonymous

yes i do

- anonymous

ok

- anonymous

i dnt noe how to get the y value?

- anonymous

ok what is your first eqution

- anonymous

do i jst plug it into the equation

- anonymous

whats the equation

- anonymous

2x+y=-7

- anonymous

Just plot 2 points and draw a straight line that goes through each of them.

- anonymous

Set x=0 for the first point and figure out what y is. Then set y = 0 for the second point and find what x is.

- anonymous

polpak i tryed that its doesnt help

- anonymous

either way i dnt need to graph them they r alrdy graphed

- anonymous

ok good

- anonymous

Oh, then just check to see which ones go through the points you plot.

- anonymous

ok i will check.

- anonymous

but do you get how to get x an y

- anonymous

no i dnt

- anonymous

yoplak you mean at which oints do they intersect

- anonymous

i tried to check on the graph and didnt understand

- anonymous

so ok diid you changed the equation they give you to y=mx+b form

- anonymous

yes

- anonymous

y=2x-7

- anonymous

what are the equations that you changed

- anonymous

the top one which is 2x+y=-7

- anonymous

ok

- anonymous

so do i jst plug in the x value that i got

- anonymous

which was -4?

- anonymous

can you attach this work and give me the linnk

- anonymous

how?

- anonymous

what numbers diid you use for x

- anonymous

ask one of your parents

- anonymous

ohh the choices u mean??

- anonymous

ok

- anonymous

a.(-4,-1) b.(-4,1) c.(4,1) d.(4,-1)

- anonymous

i think its either a or b.

- anonymous

wht is the questiom

- anonymous

solve the system by graphing

- anonymous

ok diid you grpah the equatios

- anonymous

noo they r alrdy graphed they r the choices too withthe x and y values

- anonymous

what doe the graph show does it show 2 lines crossing each other

- anonymous

yes

- anonymous

at what point do they intersect

- anonymous

in other words cross at which 2 points

- anonymous

which one??

- anonymous

a is 0 n 6 i think

- anonymous

both of the lines

- anonymous

how do i knoe they r like in the middle of 2 #s?

- anonymous

can you make an attachmen t to this work so i can see this

- anonymous

ask your mom or dad

- anonymous

so i can help you better and faster

- anonymous

i wuld have to scan it to the comp.

- anonymous

yes

- anonymous

ill see wait a lil

- anonymous

ok

- anonymous

u there

- anonymous

yes

- anonymous

diid you scan it

- anonymous

im doing it rite now

- anonymous

ok

- anonymous

what grade you in

- anonymous

8th and u??

- anonymous

me too

- anonymous

ohh

- anonymous

am good at math i diid this already

- anonymous

i knew it your were in 8th

- anonymous

ohh im not so good

- anonymous

are you finsih scaning

- anonymous

ok its saving

- anonymous

ok give me the link

- anonymous

i cant find it

- anonymous

wait a lil plz

- anonymous

ok

- anonymous

ohh it look all weird

- anonymous

how

- anonymous

##### 1 Attachment

- anonymous

let me scan it again

- anonymous

you made it uupside down

- anonymous

yea i noe im scanning it again.

- anonymous

ok how many questions you have got i can help you

- anonymous

quite a feww.

- anonymous

ok am happy to help

- anonymous

are you doing scanning

- anonymous

yes

- anonymous

ok

- anonymous

plz give me the link

- anonymous

##### 1 Attachment

- anonymous

ohh sry i gave u the wrong one

- anonymous

ok it wont open though

- anonymous

##### 1 Attachment

- anonymous

ohh that was the other side let me do it one more time srry.

- anonymous

make it clear becuse it hard to understand the questions

- anonymous

i cant see th egprah for question 3 it confusing its dark

- anonymous

i noe thats the best ican get it too

- anonymous

ok so why are the graphs colored

- anonymous

idkk

- anonymous

because on my paper they r shaded with like gray n black

- anonymous

why though

- anonymous

because thats how they r

- anonymous

heyy r u still there??

- anonymous

yes

- anonymous

ok

- anonymous

whicc question you working on

- anonymous

4.

- anonymous

its a -4,-1

- anonymous

how do u noe?

- anonymous

jst tell me how u got -1?

- anonymous

ok if you plugg -4 for bopth equations for x you r x will be -4 and y -1 for both equations

- anonymous

i pluged it in and got this

- anonymous

y=2(-4)-7

- anonymous

y=-8-7

- anonymous

which equals 15 ???

- anonymous

???

- anonymous

heyy

- anonymous

r u still there???

- anonymous

hey

- anonymous

yeah

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