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anonymous

  • 5 years ago

evaluate the following: log5 (1/125)

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  1. myininaya
    • 5 years ago
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    [ln1/125]/[ln5]=[ln125^(-1)]/[ln5]=[ln5^(-3)]/[ln5] see if that helps

  2. myininaya
    • 5 years ago
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    what do we do next

  3. myininaya
    • 5 years ago
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    you can bring that -3 down right? does anything cancel?

  4. anonymous
    • 5 years ago
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    get rid of the exponent?

  5. anonymous
    • 5 years ago
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    oh yes i was rite. um the 5's cancel rite?

  6. myininaya
    • 5 years ago
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    so we have -3(ln5)/(ln5)=-3 the ln5 cancels

  7. anonymous
    • 5 years ago
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    so where left with -3?

  8. anonymous
    • 5 years ago
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    hello?

  9. myininaya
    • 5 years ago
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    ?

  10. laloo
    • 5 years ago
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    We can write it as \[\log_{5}1-\log_{5}125 \] .................. (1) then we know that logarithm of 1 with any base is zero so the (1) becomes \[0-\log_{5}125\] ................... (2) now we can write this as \[-\log_{5}5^{3}\] ................... (3) now this becomes \[-3\times \log_{5}5 \] ................... (4) and as we know \[\log_{5}5=1 \] ...................... (5) so answer is -3

  11. anonymous
    • 5 years ago
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    i got the rite answer :) thankyou!

  12. myininaya
    • 5 years ago
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    very good thats what we got above

  13. laloo
    • 5 years ago
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    But in more simple way. :)

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