• yuki
x = cos(2t) and y = sin(2t) For this parametric eqn. I would like to find the second derivative, but I don't seem to be doing it right. This is what I tried so far. dx/dt = -2sin(2t) dy/dt = 2cos(2t) thus dy/dx = -cot(2t). for the second derivative, d/dx(dy/dx) = -csc(2t)cot(2t) so d^2/dx^2 [y] = sec^2(x)
Mathematics
• Stacey Warren - Expert brainly.com
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SOLVED
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