x = cos(2t) and y = sin(2t)
For this parametric eqn. I would like to find the second derivative, but I don't seem to be doing it
right.
This is what I tried so far.
dx/dt = -2sin(2t)
dy/dt = 2cos(2t)
thus dy/dx = -cot(2t).
for the second derivative,
d/dx(dy/dx) = -csc(2t)cot(2t)
so
d^2/dx^2 [y] = sec^2(x)

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woops, the last sentence should have been csc^2(x)

\[\frac{dy}{dx}=-\frac{\cos 2t}{\sin 2t}=-\cot 2t\]

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