anonymous
  • anonymous
gah! help again please h=2.5−ce^(−0.016t) this is the equation i have from solving dh/dt=0.016(2.5-h) now when h is at max h=2.5 how long will it take to become max (where t is time and h is hieght)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
dumbcow
  • dumbcow
unless im missing something it seems the only t that yields h of 2.5 is as t goes to infinity so you could say lim h = 2.5 as t->infinity
anonymous
  • anonymous
yeah thats why it doesnt seem to make sense, as its wanting a time for it to reach 2.5 which seems to make no sense!
dumbcow
  • dumbcow
your equation for h is correct for the given dh/dt whats the context of the problem

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
the filling of a lock in a canal, According to the mathematics of your solution, how long would it take for the lock to fill? which follows Solve the differential (dh/dt=0.016(2.5-h)) equation to find h in terms of t.
dumbcow
  • dumbcow
im guessing h needs to be 2.5 for the lock to be filled in that case the lock slowly is filled at an ever decreasing rate such that the lock is never completely full something like that would be my interpretation
anonymous
  • anonymous
yeah, the source of the questions often asks annoying questions! half the time it makes no sense!
dumbcow
  • dumbcow
good luck :)
anonymous
  • anonymous
cheers :)
anonymous
  • anonymous
the next part is Find how long it takes in minutes for the water to rise to within 2mm of the lock being completely full. so it still has to be rearranged to find that
anonymous
  • anonymous
id think anyway!
dumbcow
  • dumbcow
well for this part you can evaluate write t in terms of h h=2.5−ce^(−0.016t) ->e^(-.016t) = (2.5-h)/c ->t = -ln((2.5-h)/c)/.016 as long as h<2.5 and c > 0 t is defined plug in h = 2.5 - 2mm not sure what units the 2.5 is and of course you have to solve for c, given initial conditions do they say what the water level is at t=0 hope that helps
anonymous
  • anonymous
nope they dont ever give a value of c and thank you!

Looking for something else?

Not the answer you are looking for? Search for more explanations.