there are 12 books on algebra and calculus in a library ,the books on the same subject being different . if the numbr of selections each of whish consists 3 buks on each topic is greatest, then the numbr of books of algebra and calculus in the library is.........
a.3 & 9 b.4 & 8 c.5 & 7 d..6 & 6
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Since the group of 3 books can be found by combination, why don't we use that ?
for example, if algebra was 3 and calculus was 9, then the total number of ways that you can chose from those would be 3 * 9 = 27.
because there are 3 ways to choose an alg. book and 9 ways to choose a calc. book.
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so among a,b,c,d in your choice, you just choose the one that has the biggest value.
whats the value of log5 512
without using calculator..
conditions are give like this as...log 2 = 0.3010 and log 3 = 0.47771
so whats the value of log base5 512.?
why don't you use the fact that 512 = 2^9 ?
so log_5 (2^9) = 9 log_5 (2)
if you know how to use the change of base then that's what you will do next
idk to change the base....m the student preparing for medicine i dnt have much knowledge in math.:)
the change of base looks like this \[loga(b) = (logc(b))/(logc(a))\]
c is any number you would like it to be, in your case the base seems to be 10 since log(2) is given.
Just to let you know, we also need a log(5) as well, so make sure
that your given numbers have it. If not, you can't solve this one.
and the option is given like this a.2.70 b.2.967 c.3.876 d.3.912