there are 12 books on algebra and calculus in a library ,the books on the same subject being different . if the numbr of selections each of whish consists 3 buks on each topic is greatest, then the numbr of books of algebra and calculus in the library is......... a.3 & 9 b.4 & 8 c.5 & 7 d..6 & 6

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there are 12 books on algebra and calculus in a library ,the books on the same subject being different . if the numbr of selections each of whish consists 3 buks on each topic is greatest, then the numbr of books of algebra and calculus in the library is......... a.3 & 9 b.4 & 8 c.5 & 7 d..6 & 6

Mathematics
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Since the group of 3 books can be found by combination, why don't we use that ?
for example, if algebra was 3 and calculus was 9, then the total number of ways that you can chose from those would be 3 * 9 = 27.
because there are 3 ways to choose an alg. book and 9 ways to choose a calc. book.

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so among a,b,c,d in your choice, you just choose the one that has the biggest value.
whats the value of log5 512
without using calculator..
conditions are give like this as...log 2 = 0.3010 and log 3 = 0.47771
so whats the value of log base5 512.?
why don't you use the fact that 512 = 2^9 ?
so log_5 (2^9) = 9 log_5 (2)
if you know how to use the change of base then that's what you will do next
idk to change the base....m the student preparing for medicine i dnt have much knowledge in math.:)
the change of base looks like this \[loga(b) = (logc(b))/(logc(a))\]
c is any number you would like it to be, in your case the base seems to be 10 since log(2) is given. Just to let you know, we also need a log(5) as well, so make sure that your given numbers have it. If not, you can't solve this one.
and the option is given like this a.2.70 b.2.967 c.3.876 d.3.912
ah
so is option no c is correct.

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