A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 5 years ago

i'm unable to find the integral of sqrt(1+y'(x)^2) when y=ln(cosx)...please help

  • This Question is Closed
  1. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Start with the derivative of y, sin/cos, then use trig identity to get the two term into one. You will be left taking the integral of one trig function

  2. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    it goes to sqrt(1-tanx).....and this is where i have a problem.....

  3. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    do u have any idea ???find the next term in the sequence (6,7,9,8,6,8,?)

  4. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    You forgot to square it after you ploged it in One minus tan squared is sec squared I think, take the root and then the integral of sec

  5. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    That sequence is letters in the days of the week

  6. dumbcow
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    y' = -sin/cos y' ^2 = sin^2/cos^2 = tan^2 trig identity sec^2 = 1+tan^2 sqrt(1+y'^2) = sqrt(sec^2) = sec integral sec = ln(sec+tan) +c

  7. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.