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anonymous
 5 years ago
A pig rancher wants to enclose a rectangular area and then divide it into four pens with fencing parallel to one side of the rectangle (see the figure below). He has 620 feet of fencing available to complete the job. What is the largest possible total area of the four pens? A=2x + 5y
anonymous
 5 years ago
A pig rancher wants to enclose a rectangular area and then divide it into four pens with fencing parallel to one side of the rectangle (see the figure below). He has 620 feet of fencing available to complete the job. What is the largest possible total area of the four pens? A=2x + 5y

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0radar, I sense that you already have solved this problem. Ami I wrong?

radar
 5 years ago
Best ResponseYou've already chosen the best response.0I think you mean amount of wire used = 2x+5y then 5y=6202x 5y=(6202x) y=124(2/5)x A=x(124(2/5)x=124(2/5)x^2 dA/dx=124(4/5)x set to 0 x=155 ft y=62 ft pen will use 2(155) ft + 5(62) ft

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the pen has 5 y walls and 2 x walls

radar
 5 years ago
Best ResponseYou've already chosen the best response.0yes and as I said, 5 62 ft walls and 2 155' walls

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0not right you have to use the derivative of A= 2x+5y then solve for whats the greatest area im going to attach a picture.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x = width, which is used 5 times to make 4 pens. (620  5x)/2 = length of pens y = x(620  5x)/2 y = 310x  5/2x² The maximum area occurs at the vertex , which is at x = b/(2a) = 310/5 = 86 feet width (620 5x)/2  (620  5(62))/2 = 310/2 = 155 = combined width of all 5 pens 62 x 155 = 9610 ft² <==ANSWER

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes but i need greatest volume

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Didn't I give you the greatest area 62 x 155? The area would of been 9610 sq ft. What was the different asnwer?

radar
 5 years ago
Best ResponseYou've already chosen the best response.0You are confusing me, I took the derivative of A for area, set it to 0 and got 62 and 155. Using the restraints on the amount of wire and separate pen requirements. What was done different?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0"pen will use 2(155) ft + 5(62) ft" you did + instead of x but its all in all right work,thanks

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Glad you now understand how to solve these kind of problems. Good luck with your study efforts.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0radar, It looks like everything worked out fine. Have a good day.
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