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yuki
 5 years ago
lim (h>0) (sqrt(25+h)5)/h
I thought that f(x) = sqrt(25) therefore
the limit is = 0... but it was not right.
Can someone help me out ?
yuki
 5 years ago
lim (h>0) (sqrt(25+h)5)/h I thought that f(x) = sqrt(25) therefore the limit is = 0... but it was not right. Can someone help me out ?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Notice that this is the derivative of f(x)=sqrt(x) evaluated at 25 in disguise.

Yuki
 5 years ago
Best ResponseYou've already chosen the best response.0Oh, right, so all I am looking for is f'(5) when f'(x) = 1/(2sqrt(x)) ! Thanks a lot.
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