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think if we have the integral of x^2 from -2..2 =16/3 if we have the integral of x^2 from 0..2=8/3 if we have the integral of x^2 from -2..0=8/3 so lets think about your problem
Since it's even, the integral from -7 to -1 is the same as the integral from 1 to 7.
think about x^2 from 0..1, its 1/3 from 0..7. its 7^3/3 from -1..7 its 7^3/3+1/3
that last one is suppose to say -1..-7
is it negative -4
no what happen to x^2?
if you see what happen to x^2, you can see what will happen here
oh wait sorry i messed up on that last integral you might be right lol
Oh sorry I was figuring out the problem but you you would just flip the parameters and change the signs around right!
-4 u r right lol
from -7..-1 of x^2 its -1/3+7^3/3 to get this without integrating we just do 7^3/3-1/3 which is the integral from 0..7 minus the integral from 0..1
Okay I understand! So the integral from 1 to 0 f(x) dx = 5 changes to the integral from 0 to 1 f(x) dx = -5 and you add it to the integral from 0 to 7 which is 1 making -4