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anonymous

  • 5 years ago

Suppose that f(x) is an EVEN function and let the integral f(x) dx from 0 to 1=5 and the integral f(x) dx from 0 to 7 =1. What is the integral from f(x) dx from -7 to -1?

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  1. myininaya
    • 5 years ago
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    think if we have the integral of x^2 from -2..2 =16/3 if we have the integral of x^2 from 0..2=8/3 if we have the integral of x^2 from -2..0=8/3 so lets think about your problem

  2. anonymous
    • 5 years ago
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    Since it's even, the integral from -7 to -1 is the same as the integral from 1 to 7.

  3. myininaya
    • 5 years ago
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    right

  4. myininaya
    • 5 years ago
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    think about x^2 from 0..1, its 1/3 from 0..7. its 7^3/3 from -1..7 its 7^3/3+1/3

  5. myininaya
    • 5 years ago
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    that last one is suppose to say -1..-7

  6. anonymous
    • 5 years ago
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    is it negative -4

  7. myininaya
    • 5 years ago
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    no what happen to x^2?

  8. myininaya
    • 5 years ago
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    if you see what happen to x^2, you can see what will happen here

  9. myininaya
    • 5 years ago
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    oh wait sorry i messed up on that last integral you might be right lol

  10. anonymous
    • 5 years ago
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    Oh sorry I was figuring out the problem but you you would just flip the parameters and change the signs around right!

  11. myininaya
    • 5 years ago
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    -4 u r right lol

  12. myininaya
    • 5 years ago
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    from -7..-1 of x^2 its -1/3+7^3/3 to get this without integrating we just do 7^3/3-1/3 which is the integral from 0..7 minus the integral from 0..1

  13. anonymous
    • 5 years ago
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    Okay I understand! So the integral from 1 to 0 f(x) dx = 5 changes to the integral from 0 to 1 f(x) dx = -5 and you add it to the integral from 0 to 7 which is 1 making -4

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