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\[\sum_{n=2}^{infinity} 1/n \sqrt{\ln(n)}\]

do you know what test to use?

my original thought was ratio, but i dont know how to apply that here

I'm wanting to say it has something to do with the Cauchy Criterion

...I have no idea what that means..haha

I don't think we covered that

Oh, the ratio test should work.

really? Let me try that really quickly

Well, that gave me infinity over infinity...maybe i'm doing it wrong?

Looking up properties of the natural log right now, give me a sec.

thanks so much!

Integral test would be easier since i see ln(n) and 1/n there.

oh that makes sense!

hmm. Ok, let me think about that for a min :)

hmm actually that might not work cause the ration needs to be less than 1 for the ratio test to work

when i worked it doing the integral test i got infinity meaning divergent does that seem right?