anonymous 5 years ago What is the domain of 1/sqrt3x+1?

1. myininaya

$1/{\sqrt{3x+1}}$

2. myininaya

is that what is says?

3. anonymous

Yes.

4. myininaya

ok when is the bottom zero

5. Yuki

since the denominator is not allowed to be 0 and the input of the square root is not allowed to be negative, you solve for sqrt(3x+1) = 0 and 3x+1 < 0 The solution of these are the x's you are not allowed to use. so the domain would be all real numbers except the above.