## anonymous 5 years ago The question is: Which is the graph of the given function? f(t)= =-1/4tan (1/8πt)

1. anonymous

2. anonymous

b http://www.wolframalpha.com/input/?i=plot+-1%2F4tan+%281%2F8%CF%80t%29 $\tan (u) = \sin (u)\div \cos (u)$ sin(0) = 0 hence tan()n will always pass trough (0,0) the origin. 1/4 is about how soon the the graph will approach the vertical asymptotes. and the (1/8)pi is about how stretched the graph is.

3. anonymous