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anonymous

  • 5 years ago

The question is: Which is the graph of the given function? f(t)= =-1/4tan (1/8πt)

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  1. anonymous
    • 5 years ago
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  2. anonymous
    • 5 years ago
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    b http://www.wolframalpha.com/input/?i=plot+-1%2F4tan+%281%2F8%CF%80t%29 \[\tan (u) = \sin (u)\div \cos (u)\] sin(0) = 0 hence tan()n will always pass trough (0,0) the origin. 1/4 is about how soon the the graph will approach the vertical asymptotes. and the (1/8)pi is about how stretched the graph is.

  3. anonymous
    • 5 years ago
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    thanks for your help

  4. anonymous
    • 5 years ago
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    tan(x) vs -tan(x) plot tan(x), -(tan(x)) -tan(x) vs -1/4(tan(x)) http://www.wolframalpha.com/input/?i=plot+++-tan%28x%29%2C+-1%2F4%28tan%28x%29%29 -1/4(tan(x)) vs. -1/4(tan((1/8)*pi*x)) http://www.wolframalpha.com/input/?i=plot+++-1%2F4%28tan%28x%29%29%2C+-1%2F4%28tan%28%281%2F8%29*pi*x%29%29+for+x%3D+-6+to+x+%3D+6

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