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anonymous

  • 5 years ago

Find the of x for which the geometric series converges. [(x-1)/2]^n-1

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  1. anonymous
    • 5 years ago
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    Find the * value* of x..

  2. anonymous
    • 5 years ago
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    Do you think you could help chaguanas?

  3. anonymous
    • 5 years ago
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    Let's see, checking my book

  4. anonymous
    • 5 years ago
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    What you do is write a few values of the series, giving n value 1, then 2, then 3. After a few you would know what the sum looks like. Then you can find x

  5. anonymous
    • 5 years ago
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    I'm not sure what the series would even be written out as... :/

  6. anonymous
    • 5 years ago
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    Oh, I'm sorry. Your note confused me when you said find value of x.

  7. anonymous
    • 5 years ago
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    Oh, i left that part out of the original question, so I was just throwing that in that there...

  8. anonymous
    • 5 years ago
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    So how should i go about this?

  9. anonymous
    • 5 years ago
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    Ratio test

  10. anonymous
    • 5 years ago
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    I would say x=1. Ratio test, take limit leaves x-1. Not confident on my answer. May be Xavier can check me.

  11. anonymous
    • 5 years ago
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    ok. Thanks!

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spraguer (Moderator)
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