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anonymous
 5 years ago
Find the of x for which the geometric series converges. [(x1)/2]^n1
anonymous
 5 years ago
Find the of x for which the geometric series converges. [(x1)/2]^n1

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Find the * value* of x..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you think you could help chaguanas?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Let's see, checking my book

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What you do is write a few values of the series, giving n value 1, then 2, then 3. After a few you would know what the sum looks like. Then you can find x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm not sure what the series would even be written out as... :/

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh, I'm sorry. Your note confused me when you said find value of x.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh, i left that part out of the original question, so I was just throwing that in that there...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So how should i go about this?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I would say x=1. Ratio test, take limit leaves x1. Not confident on my answer. May be Xavier can check me.
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