anonymous
  • anonymous
log base 8 (0.25) compute the log
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
-2/3
anonymous
  • anonymous
You can think of it as => 8^(x) = 0.25? What does x need to be.
dumbcow
  • dumbcow
you could also use change of base formula =ln(0.25)/ln(8)

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anonymous
  • anonymous
when i tried to solve it I broke it down to 8^y = 25/100. simplifed and got 8^y = 1/4. 2^3= 1/2^2. the i got stuck
anonymous
  • anonymous
i know change of base works but i must show work
anonymous
  • anonymous
8^x = 1/4 we know x has to be -, 8^(2/3) = 4
anonymous
  • anonymous
Or if you're like me and you can never remember the change of base formula... Let \(k=log_8 (.25)\) \[\implies 8^k = .25\] \[\implies k(ln8) = ln (.25)\] \[\implies k = \frac{ln(.25)}{ln8}\] \[\implies log_8(.25) = \frac{ln(.25)}{ln8}\]
anonymous
  • anonymous
8^2 = 64 third root of 64 = 4. The way you are showing you work if you can reason that.
anonymous
  • anonymous
Ok I see

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