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anonymous

  • 5 years ago

state the domain and range f(x)=2(1/3)^x

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  1. anonymous
    • 5 years ago
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    domain all of real range is positive R

  2. anonymous
    • 5 years ago
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    howd you get that?

  3. anonymous
    • 5 years ago
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    all the possible values of x which satisfies the relation will give you the domain.. n for every x the outcome gives you the range

  4. anonymous
    • 5 years ago
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    Basically you're looking for disallowed values for x. If for example you had \(\sqrt{x}\) for your function you would know that negative numbers for x are not allowed. If you had \(\frac{4}{x}\) then 0 would not be allowed. If you had \(\sqrt{5-x}\) then your domain would be numbers less than or equal to 5. etc

  5. anonymous
    • 5 years ago
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    shouldnt they be numbers?

  6. anonymous
    • 5 years ago
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    The domain and range are sets of numbers. There are many values you can plug in for x and get many different values for the function.

  7. anonymous
    • 5 years ago
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    so why is the domain and range not numbers?

  8. anonymous
    • 5 years ago
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    it is a set of numbers

  9. anonymous
    • 5 years ago
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    ????

  10. anonymous
    • 5 years ago
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    you dont understand what is meant by a "set of numbers"??

  11. anonymous
    • 5 years ago
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    i just dont understand what your saying

  12. anonymous
    • 5 years ago
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    {1, 2, 3.4, 15} is a set of 4 numbers. (-5,1) is a set of infinitely many numbers between -5 and 1, but not including -5 or 1

  13. anonymous
    • 5 years ago
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    i get that!!! I just dont understand the domain and range

  14. anonymous
    • 5 years ago
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    Well the domain is just a set of numbers that are 'legal' to plug in for x.

  15. anonymous
    • 5 years ago
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    If your function is well behaved (doesn't divide or take the square root) then anything is legal. Otherwise you might have to restrict what x can be. If you divide by x, then x cannot be 0. If you divide by x+3 then x cannot be -3. If you take the square root of x, then x cannot be negative, etc.

  16. anonymous
    • 5 years ago
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    i dont get it

  17. anonymous
    • 5 years ago
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    Can you take the square root of a negative number?

  18. anonymous
    • 5 years ago
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    (and get a real result)

  19. anonymous
    • 5 years ago
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    I have to go, but we can talk about it another time if you like.

  20. anonymous
    • 5 years ago
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    margaret are you aware of complex numbers?

  21. anonymous
    • 5 years ago
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    no im not of complex numbers

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