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anonymous
 5 years ago
state the domain and range f(x)=2(1/3)^x
anonymous
 5 years ago
state the domain and range f(x)=2(1/3)^x

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0domain all of real range is positive R

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0all the possible values of x which satisfies the relation will give you the domain.. n for every x the outcome gives you the range

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Basically you're looking for disallowed values for x. If for example you had \(\sqrt{x}\) for your function you would know that negative numbers for x are not allowed. If you had \(\frac{4}{x}\) then 0 would not be allowed. If you had \(\sqrt{5x}\) then your domain would be numbers less than or equal to 5. etc

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0shouldnt they be numbers?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The domain and range are sets of numbers. There are many values you can plug in for x and get many different values for the function.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so why is the domain and range not numbers?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it is a set of numbers

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you dont understand what is meant by a "set of numbers"??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i just dont understand what your saying

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0{1, 2, 3.4, 15} is a set of 4 numbers. (5,1) is a set of infinitely many numbers between 5 and 1, but not including 5 or 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i get that!!! I just dont understand the domain and range

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well the domain is just a set of numbers that are 'legal' to plug in for x.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If your function is well behaved (doesn't divide or take the square root) then anything is legal. Otherwise you might have to restrict what x can be. If you divide by x, then x cannot be 0. If you divide by x+3 then x cannot be 3. If you take the square root of x, then x cannot be negative, etc.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can you take the square root of a negative number?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(and get a real result)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I have to go, but we can talk about it another time if you like.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0margaret are you aware of complex numbers?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no im not of complex numbers
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