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anonymous

  • 5 years ago

Find the Vertex and all Intercepts of the parabola. f(x)=2x^2-4x This is a practice one; however I am having trouble understanding how to get to the point where I need to sketch it on the graph and determine my values..

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  1. anonymous
    • 5 years ago
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    Do you know how to complete the square?

  2. anonymous
    • 5 years ago
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    And are you in a calculus course?

  3. anonymous
    • 5 years ago
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    Not really...I've been looking at this and i'm completely lost. Strange, but when i get to this type of problem, I go blank. Obviously I can graph it, but can't figure out how to solve it.

  4. anonymous
    • 5 years ago
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    Well finding the intercepts is easy enough. For the x-intercepts we will set y= 0 For the y-intercepts we will set x=0 For the vertex read this: http://www.purplemath.com/modules/sqrvertx.htm

  5. anonymous
    • 5 years ago
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    y = x(2x - 4) set y = 0 which means either x = 0 or 2x-4=0 x=2,

  6. anonymous
    • 5 years ago
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    Tell me if you need clarification on anything! =D

  7. anonymous
    • 5 years ago
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    Ill look at that link to see if I can figure out the vertex Thank you for your help

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