Supposef'(2) = 4, g'(2) = -3, f(2) = -1, g(2) = 2, find the derivative at 2 for: s(x)=f(x)+5g(x) Somebody help?

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Supposef'(2) = 4, g'(2) = -3, f(2) = -1, g(2) = 2, find the derivative at 2 for: s(x)=f(x)+5g(x) Somebody help?

Mathematics
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so you are looking for s'(2)?
yes
How do I do that?

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well then s'(x) = f'(x) +5g'(x) f(2) and g(2) don't seem to be needed
true. wht do I do?
just plug in your values it seems.
What values? Can you guide me?
http://www.hyper-ad.com/tutoring/math/calculus/Properties_of_Derivatives.html
I got it, but how about h(x) = f(g(x))? h'(2)= ... ?
on that link scroll down to the chain rule.
I see, but im still confused. :/

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