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anonymous
 5 years ago
Supposef'(2) = 4, g'(2) = 3, f(2) = 1, g(2) = 2, find the derivative at 2 for:
s(x)=f(x)+5g(x)
Somebody help?
anonymous
 5 years ago
Supposef'(2) = 4, g'(2) = 3, f(2) = 1, g(2) = 2, find the derivative at 2 for: s(x)=f(x)+5g(x) Somebody help?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so you are looking for s'(2)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well then s'(x) = f'(x) +5g'(x) f(2) and g(2) don't seem to be needed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just plug in your values it seems.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What values? Can you guide me?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0http://www.hyperad.com/tutoring/math/calculus/Properties_of_Derivatives.html

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I got it, but how about h(x) = f(g(x))? h'(2)= ... ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0on that link scroll down to the chain rule.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I see, but im still confused. :/
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