Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.

- anonymous

Explain local linear approximation and how to do it please?

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions.

Get your **free** account and access **expert** answers to this and **thousands** of other questions

- anonymous

Explain local linear approximation and how to do it please?

- schrodinger

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

Of one variable or two? Are you in Cal I?

- anonymous

I think it's 1 variable. Here's the question:
For the function f, f ' (x)=2x+1 and f(1) = 4. What is the approximation for f(1.2) found by using the line tangent to the graph of f at x=1?
I'm in AP Calc AB

- anonymous

Because it is a AP question, there is a lot of trickery involved rather than a straightforward question. You can start of by finding f(x). I imagine that would be the integral of f'(x)=2x+1

Looking for something else?

Not the answer you are looking for? Search for more explanations.

- anonymous

I imagine f(1)=4 should have been f'(1)=4?

- anonymous

no it just says f(1) = 4.
I got x^2 + x + C as f(x) through integration. I remember you're supposed to do local linear approximation to find C, but I don't remember how & I can't find my notes from that day.

- anonymous

Local linear approximation would be f(1)+f'(1)(1)(1.2-1)

- anonymous

Decoding that: evaluate f at one, add to (f' evaluated at one, multiplied by 1.2-1). I accidentally wrote an extra (1) above.

- anonymous

So 4.6? Thanks so much.

- anonymous

I think there is a clue in there find C. f(1)=4. so therefore (1^2) +1 + C=4 Solve for C

- anonymous

Check your answer. Redo everything with the value f(x)=x^2+x+2 (Now that we know the value of C.

Looking for something else?

Not the answer you are looking for? Search for more explanations.