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anonymous

  • 5 years ago

Solve for x: square route of 3x^2-8 (end square route) + x=0

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  1. anonymous
    • 5 years ago
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    To solve when there is a square root involved. you need to get the square root by itself on one side of the equation... So you would subtract x

  2. anonymous
    • 5 years ago
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    sqrt(3x^2 - 8) = -x

  3. anonymous
    • 5 years ago
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    Then you square both sides.

  4. anonymous
    • 5 years ago
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    sqrt(3x^2 - 8)^2 = (-x)^2 squaring a square root cancels each other out leaving you with what is left under the square root sign 3x^2 - 8 = x^2

  5. anonymous
    • 5 years ago
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    Make the equation = to 0 2x^2 - 8 = 0

  6. anonymous
    • 5 years ago
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    Factor 2(x^2 - 4) = 0 2(x + 2)(x - 2) = 0 x = -2 or x = 2

  7. anonymous
    • 5 years ago
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    Thanks!

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