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anonymous
 5 years ago
OK, I can't figure this improper integral out  I keep getting ln2 and the answer is supposed to be ln2; integrate from 1 to infinity dx/(x^2+5x+6); I've tried partial fractions  but that doesn't seem to work because I get 1/(x+2) + 0/(x+3) . . . and I can't do anything with that! Help!
anonymous
 5 years ago
OK, I can't figure this improper integral out  I keep getting ln2 and the answer is supposed to be ln2; integrate from 1 to infinity dx/(x^2+5x+6); I've tried partial fractions  but that doesn't seem to work because I get 1/(x+2) + 0/(x+3) . . . and I can't do anything with that! Help!

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0For the partial fractions, did you get 1=A(x+2)+B(x+3). This works out.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, I'll try again . . . I know I'm tired . . . so I'll try again!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0SO . . . this time I got 1/(x+2) and 1/(x+3) . . . ?? that would mean that 1/(x^2+5x+6) = 1/((x+2) 1/((x+3) . . . am I on the right track?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thanks for your help . . . I'll keep working. Have a good evening.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thats what i got for the decomposition. Good luck
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