## anonymous 5 years ago points of discontinuity? y = cot x, [0, 2 $\pi$ ]

1. anonymous

$\cot(x) = {1 \over \tan(x)}$ so there's a discontinuity, whenever tan(x) == 0... 'cause a division by 0 is not defined.

2. anonymous

cotx = (cosx)/(sinx) Where is this function not defined? i.e. where is sin(x)=0? Because at this point, cotx will be undefined because you cannot divide by zero. So find all points from 0 to 2 pi where sinx is 0.

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