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anonymous
 5 years ago
points of discontinuity?
y = cot x, [0, 2 \[\pi \] ]
anonymous
 5 years ago
points of discontinuity? y = cot x, [0, 2 \[\pi \] ]

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\cot(x) = {1 \over \tan(x)}\] so there's a discontinuity, whenever tan(x) == 0... 'cause a division by 0 is not defined.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0cotx = (cosx)/(sinx) Where is this function not defined? i.e. where is sin(x)=0? Because at this point, cotx will be undefined because you cannot divide by zero. So find all points from 0 to 2 pi where sinx is 0.
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