anonymous
  • anonymous
\[\lim_{n \rightarrow 0} \ [\sin3x \sin2x\ ]\]
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Its [sin3x/ sin2x]
anonymous
  • anonymous
This one requires a little trickery. There is an identity that says sinx/x=1 (sinofantything/anything=1. So you have work some magic to make it (sin3x/3x)/(sin2x/2x)
anonymous
  • anonymous
The limit of sinx over x as x approaches to 0 equals 1 is not an identity but a theorem. Looking back to the question, the answer is 3/2.

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