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anonymous

  • 5 years ago

Don't get this step. x^2+y^2=3y. then it says x^2+(y-3/2)^2= (3/2)^2 . where does the 3/2 come from?

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  1. anonymous
    • 5 years ago
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    I should mention this is finding a Cartesian equation. r=3sin(theta)

  2. anonymous
    • 5 years ago
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    Took the 3y to the other side and complate that square.

  3. myininaya
    • 5 years ago
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    they seen it was a cirlce so they wrote it in the standard from of a circle

  4. myininaya
    • 5 years ago
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    x^2+y^2-3y=0 (x-0)^2+y^2-3y+(3/2)^2=(3/2)^2 (x-0)^2+(y-3/2)^2=(3/2)^2

  5. anonymous
    • 5 years ago
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    ...This Calculus thing would be a whole lot easier if I ever actually learned Algebra. Thanks guys!

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