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anonymous
 5 years ago
what is surface of revolution of y=(x^2+1)^(1/2), [0<x<3]
anonymous
 5 years ago
what is surface of revolution of y=(x^2+1)^(1/2), [0<x<3]

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think they are trying to say find the integral over 0 to 3.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there is no such thing as the integral of (2x^2+1)^(1/2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am not sure what you are working on in class. Usually when I see questions like this they something like what is the volume of the solid revolved around a certain x or y. But you can integrate this, let u=2x^2+1 then when you get dx you can solve for u and substitute for x.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes that is ture but, the du doesnt cancel out the x that is there cause of the equation
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