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In Session 60 recitation, the problem required computing the antiderivative of (1500/100+(t50)^2)7. I understand to use substitution but how did it simplify to be the arctan?
 2 years ago
 2 years ago
In Session 60 recitation, the problem required computing the antiderivative of (1500/100+(t50)^2)7. I understand to use substitution but how did it simplify to be the arctan?
 2 years ago
 2 years ago

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hburgielBest ResponseYou've already chosen the best response.1
If you use the substitution t5 = 10 tan(theta) then, after you integrate and reverse the substitution, you get theta = arctan((t5)/10). I hope that answers your question!
 2 years ago
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