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  • 5 years ago

In Session 60 recitation, the problem required computing the anti-derivative of (1500/100+(t-50)^2)-7. I understand to use substitution but how did it simplify to be the arctan?

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  1. hburgiel
    • 4 years ago
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    If you use the substitution t-5 = 10 tan(theta) then, after you integrate and reverse the substitution, you get theta = arctan((t-5)/10). I hope that answers your question!

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