anonymous
  • anonymous
Each of the numbers 1-9 is written on a different golf ball. the ten golf balls are put in a paper bag. If one of the golf balls is selected at random from the bag, find the probability that the number selected is greater then 5
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
First of all you have numbers 1-9 and 10 golf balls... we will have to get that straightened out first.
anonymous
  • anonymous
i don't know thats the question. i am assuming its a typo
anonymous
  • anonymous
go with 9 golf balls total

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anonymous
  • anonymous
I would say then 1-10 are written... let's go with that. So.. how many are greater than 5
anonymous
  • anonymous
oops the numbers are 0-10 my typo
anonymous
  • anonymous
Probability is the outcome in question divided by all the possible outcomes. How many golf balls have numbers greater than five? That's the number on top (numerator). How many golf balls are there in all? That's the number on the bottom (denominator).
anonymous
  • anonymous
4/10
anonymous
  • anonymous
its that simple
anonymous
  • anonymous
0 - 10 doesn't solve the problem though; that's 11 numbers
anonymous
  • anonymous
I would say 5/10 because I think they meant for it to be 1-10 which would then be 1/2
anonymous
  • anonymous
0-9 so sorry hard to have 2 pages up
anonymous
  • anonymous
so 4/10
anonymous
  • anonymous
which then you divide 4 by 10 right?
anonymous
  • anonymous
If you say 4/10 assuming 0 - 9 then you reduce that fraction. Probability is usually written as fractions. 2/5 so it will happen 2 out of every 5 times you do it.

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