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anonymous

  • 5 years ago

Each of the numbers 1-9 is written on a different golf ball. the ten golf balls are put in a paper bag. If one of the golf balls is selected at random from the bag, find the probability that the number selected is greater then 5

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  1. anonymous
    • 5 years ago
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    First of all you have numbers 1-9 and 10 golf balls... we will have to get that straightened out first.

  2. anonymous
    • 5 years ago
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    i don't know thats the question. i am assuming its a typo

  3. anonymous
    • 5 years ago
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    go with 9 golf balls total

  4. anonymous
    • 5 years ago
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    I would say then 1-10 are written... let's go with that. So.. how many are greater than 5

  5. anonymous
    • 5 years ago
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    oops the numbers are 0-10 my typo

  6. anonymous
    • 5 years ago
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    Probability is the outcome in question divided by all the possible outcomes. How many golf balls have numbers greater than five? That's the number on top (numerator). How many golf balls are there in all? That's the number on the bottom (denominator).

  7. anonymous
    • 5 years ago
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    4/10

  8. anonymous
    • 5 years ago
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    its that simple

  9. anonymous
    • 5 years ago
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    0 - 10 doesn't solve the problem though; that's 11 numbers

  10. anonymous
    • 5 years ago
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    I would say 5/10 because I think they meant for it to be 1-10 which would then be 1/2

  11. anonymous
    • 5 years ago
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    0-9 so sorry hard to have 2 pages up

  12. anonymous
    • 5 years ago
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    so 4/10

  13. anonymous
    • 5 years ago
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    which then you divide 4 by 10 right?

  14. anonymous
    • 5 years ago
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    If you say 4/10 assuming 0 - 9 then you reduce that fraction. Probability is usually written as fractions. 2/5 so it will happen 2 out of every 5 times you do it.

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