## anonymous 5 years ago Each of the numbers 1-20 is written on a ball and placed in a bag. if 2 of the 20 balls are selected from the bag at random, without replacement, find the probability that the first number is less then 7 and the second number is even

1. anonymous

I believe you will do this $(6\20)\times (10 \19)$ The reason is because your first ball you want to be less than seven so the prob. is the six balls out of the twenty. Then you times it by the 10 even numbers found in 20 and because there is no replacement there is no longer 20 balls but 19

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