anonymous
  • anonymous
find the exact perimiter of the rectangle. then approximate your answer. square root 18cm and square root 72cm
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
\[\sqrt{18} and \sqrt{72}\]
radar
  • radar
\[2\sqrt{18}+2\sqrt{72}=6\sqrt{2}+6\sqrt{2}=12\sqrt{2}\]
radar
  • radar
Any questions?

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anonymous
  • anonymous
ok I get
radar
  • radar
Good
anonymous
  • anonymous
how do I get the approx?
anonymous
  • anonymous
doesnt seem to work right I get 0
radar
  • radar
I would approximate the sq rt of 2 as 2.14 as it is an irrational value
radar
  • radar
excuse me 1.414 lol
anonymous
  • anonymous
that doesnt seem right either it says 14 and it should be in the 100s?
radar
  • radar
The perimeter is approx 17
radar
  • radar
How do you figure in the 100s?
anonymous
  • anonymous
ok
radar
  • radar
The sides are 4.3 cm and 8.5 cm add up the 4 sides for perimeter 8.6 +17=25.6 which is quite a bit diffrerent than 17.......thinking
radar
  • radar
I see the problem\[2\sqrt{72}=12\sqrt{2}\] not 6 sq r2 2
radar
  • radar
\[6\sqrt{2}+12\sqrt{2}=18\sqrt{2}\] thats more better.
radar
  • radar
That is the exact , the approximate is 25.45 cm
radar
  • radar
did you see where I goofed\[2\sqrt{72}=2\sqrt{36}\sqrt{2}=12\sqrt{2}\]
radar
  • radar
Is it clear now SaraJ?"
anonymous
  • anonymous
Yes I was wondering why it wasnt comming out right, LoL

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