find the exact perimiter of the rectangle. then approximate your answer. square root 18cm and square root 72cm

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find the exact perimiter of the rectangle. then approximate your answer. square root 18cm and square root 72cm

Mathematics
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\[\sqrt{18} and \sqrt{72}\]
\[2\sqrt{18}+2\sqrt{72}=6\sqrt{2}+6\sqrt{2}=12\sqrt{2}\]
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Other answers:

ok I get
Good
how do I get the approx?
doesnt seem to work right I get 0
I would approximate the sq rt of 2 as 2.14 as it is an irrational value
excuse me 1.414 lol
that doesnt seem right either it says 14 and it should be in the 100s?
The perimeter is approx 17
How do you figure in the 100s?
ok
The sides are 4.3 cm and 8.5 cm add up the 4 sides for perimeter 8.6 +17=25.6 which is quite a bit diffrerent than 17.......thinking
I see the problem\[2\sqrt{72}=12\sqrt{2}\] not 6 sq r2 2
\[6\sqrt{2}+12\sqrt{2}=18\sqrt{2}\] thats more better.
That is the exact , the approximate is 25.45 cm
did you see where I goofed\[2\sqrt{72}=2\sqrt{36}\sqrt{2}=12\sqrt{2}\]
Is it clear now SaraJ?"
Yes I was wondering why it wasnt comming out right, LoL

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