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anonymous

  • 5 years ago

find the exact perimiter of the rectangle. then approximate your answer. square root 18cm and square root 72cm

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  1. anonymous
    • 5 years ago
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    \[\sqrt{18} and \sqrt{72}\]

  2. radar
    • 5 years ago
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    \[2\sqrt{18}+2\sqrt{72}=6\sqrt{2}+6\sqrt{2}=12\sqrt{2}\]

  3. radar
    • 5 years ago
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    Any questions?

  4. anonymous
    • 5 years ago
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    ok I get

  5. radar
    • 5 years ago
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    Good

  6. anonymous
    • 5 years ago
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    how do I get the approx?

  7. anonymous
    • 5 years ago
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    doesnt seem to work right I get 0

  8. radar
    • 5 years ago
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    I would approximate the sq rt of 2 as 2.14 as it is an irrational value

  9. radar
    • 5 years ago
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    excuse me 1.414 lol

  10. anonymous
    • 5 years ago
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    that doesnt seem right either it says 14 and it should be in the 100s?

  11. radar
    • 5 years ago
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    The perimeter is approx 17

  12. radar
    • 5 years ago
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    How do you figure in the 100s?

  13. anonymous
    • 5 years ago
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    ok

  14. radar
    • 5 years ago
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    The sides are 4.3 cm and 8.5 cm add up the 4 sides for perimeter 8.6 +17=25.6 which is quite a bit diffrerent than 17.......thinking

  15. radar
    • 5 years ago
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    I see the problem\[2\sqrt{72}=12\sqrt{2}\] not 6 sq r2 2

  16. radar
    • 5 years ago
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    \[6\sqrt{2}+12\sqrt{2}=18\sqrt{2}\] thats more better.

  17. radar
    • 5 years ago
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    That is the exact , the approximate is 25.45 cm

  18. radar
    • 5 years ago
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    did you see where I goofed\[2\sqrt{72}=2\sqrt{36}\sqrt{2}=12\sqrt{2}\]

  19. radar
    • 5 years ago
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    Is it clear now SaraJ?"

  20. anonymous
    • 5 years ago
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    Yes I was wondering why it wasnt comming out right, LoL

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