anonymous
  • anonymous
The table lists data regarding the average salaries of several professional athletes in the years 1991 and 2001. a) Use the data points to find a linear function that fits the data . b) Use the function to predict the average salary in 2005 and 2010. Year 1991 the average salary is 269,000 year 2010 the average salary is 1,390,000
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Treat this as a linear equation (y=mx+b). The year is your x value, and the salary is your y-value, so you really have two ordered pairs - (1991, 269000) and (2010, 1390000). Use these to find the slope (m) of your line.
anonymous
  • anonymous
Once you have the slope, then use the values from one of the ordered pairs to find the y-intercept (b).
anonymous
  • anonymous
I need to solve the linear function that fits data S(x)= And then predicted the average salary for 2005 and 2010?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Is the data you listed above all of the data that is given?
anonymous
  • anonymous
yes sir!
anonymous
  • anonymous
Then what I said above should work, though your equation will take the form S(x)=mx+b, since it is supposed to be a function. Use the ordered pairs to find the slope (change in y value over change in x value).
anonymous
  • anonymous
Plug the two points into the slope formula to find the slope of the linear function. Then plug the slope and one of the points into the point slope formula: \[y-y_1 = m(x-x_1)\] Where \((x_1,y_1)\) is one of your points and m is the slope.
anonymous
  • anonymous
That make no scence to me at all.....!
anonymous
  • anonymous
Ok, do you know the formula for the slope if you have 2 points?
anonymous
  • anonymous
x1 and y2 over x2 and y2 but it is hard for to get the answer
anonymous
  • anonymous
That's not quite right. \[\frac{y_2-y_1}{x_2-x1} = Slope\]
anonymous
  • anonymous
ok
anonymous
  • anonymous
So plug in the salaries as y2 and y1 and the years as x2 and x1. Make sure you keep them consistent, so the salary for one year is y2 then that year must be x2.
anonymous
  • anonymous
And then post what you get for slope
anonymous
  • anonymous
11,210,000 over 19
anonymous
  • anonymous
You have an extra 0 there. Should be 1,121,000 over 19
anonymous
  • anonymous
Ok, so now plug in that slope, along with one of your two points into the point slope formula.
anonymous
  • anonymous
yea sry so the answer is 1,121,000 over 19 is s(x)?
anonymous
  • anonymous
No, that's the slope of your line.
anonymous
  • anonymous
Now you plug in that slope along with one of your points into the point slope formula: \[y-y_1 = m(x-x_1)\] Where \(x_1,y_1\) are the x and y values of your point, and m is the slope.
anonymous
  • anonymous
I am lost!!!! SRY
anonymous
  • anonymous
You have the slope. The slope is m. you have 2 points. Pick one.
anonymous
  • anonymous
I am not good at this type of question
anonymous
  • anonymous
Which point do you want to use?
anonymous
  • anonymous
269,000
anonymous
  • anonymous
That's a salary, the point would be (1991,269,000)
anonymous
  • anonymous
1991
anonymous
  • anonymous
Where 1991 is your \(x_1\) and 269,000 is your \(y_1\). Plug them into the equation and plug in the slope you found for m. That will give you the equation for the line which represents the salary over time.
anonymous
  • anonymous
so what is s(x)= then
anonymous
  • anonymous
After you plug it in, s(x) = y
anonymous
  • anonymous
I also have to predict the salary for 2005 and 2010?
anonymous
  • anonymous
Which you can do easily once you have the formula. Have you plugged it in yet?
anonymous
  • anonymous
so you have 1,120,000/9=124,444
anonymous
  • anonymous
No.
anonymous
  • anonymous
1,120,000/19=58,947
anonymous
  • anonymous
I am so confused!!!!
anonymous
  • anonymous
You picked your point, so you should have \[y - 269,000 = \frac{1,121,000}{19}(x - 1991)\]
anonymous
  • anonymous
well 1,121,000 / 19=59,000
anonymous
  • anonymous
Solving for s(x) = y we have: \[ s(x) = y = \frac{1}{19}(1,121,000x -2226800000)\]
anonymous
  • anonymous
ok
anonymous
  • anonymous
So that's the equation for the salary at a given year x.
anonymous
  • anonymous
You want to know the salary at 2010, plug that in for x, and see what y is.
anonymous
  • anonymous
or s(x), whichever you prefer.
anonymous
  • anonymous
2,030,530,000
anonymous
  • anonymous
26,410,000 to many zero when working
anonymous
  • anonymous
2010 would be 26,410,000 and 2005 would be 20,805,000
anonymous
  • anonymous
I am sorry if I am causing you grief I am just bad at these problem.

Looking for something else?

Not the answer you are looking for? Search for more explanations.