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anonymous

  • 5 years ago

Find the interval of convergence of the sum of (x-2)^n divided by the square root of n.

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  1. anonymous
    • 5 years ago
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    The answer is [1,3), how did they get to that?

  2. anonymous
    • 5 years ago
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    I'm doing the problem...

  3. anonymous
    • 5 years ago
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    Do you know how to find the biggest chunk of the interval of convergence?

  4. anonymous
    • 5 years ago
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    That is, I'm asking if it's only the end points you're having trouble with.

  5. anonymous
    • 5 years ago
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    ?

  6. anonymous
    • 5 years ago
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    oh sorry, i actually figured out what i did wrong. Thanks tho!

  7. anonymous
    • 5 years ago
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    while you're hear though.... how do you do term by term multiplication in a series? i have to find the first four nonzero of the MacLaurin series sinx *cosx

  8. anonymous
    • 5 years ago
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    Anyway, the series is convergent for x such that\[\lim_{n \rightarrow \infty}\ \left| \frac{(x-2)^{n+1}/\sqrt{n+1}}{(x-2)^n/\sqrt{n}} \right|<1\] by the ratio test, and then check for convergence at each of the end points, x=1 and x=3. Convergent for 1 by alternating series test, and non-convergent for 3 by integral test, say.

  9. anonymous
    • 5 years ago
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    You form the Cauchy product.

  10. anonymous
    • 5 years ago
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    does anyone know how i can scan my paper

  11. anonymous
    • 5 years ago
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    \[\left( \sum_{}{}a_n \right)\left( \sum_{}{}b_n \right)=\sum_{}{}c_n\]where\[c_n=\sum_{k=0}^{n}a_kb_{n-k}\]

  12. anonymous
    • 5 years ago
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    does anyone know how i can scan my paper

  13. anonymous
    • 5 years ago
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    You need a scanner to scan your paper, mary :)

  14. anonymous
    • 5 years ago
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    tell me steps to scan my paper

  15. anonymous
    • 5 years ago
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    \[\sum_{n=0}^{\infty}c_n=\sum_{n=0}^{\infty}\left( \sum_{k=0}^{n}a_kb_{n-k} \right)\]

  16. anonymous
    • 5 years ago
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    Well, it depends on your software and machinery. They're not all the same. You have to make sure your scanner is connected to your computer, either through a cable or wireless, and use the appropriate software.

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