anonymous
  • anonymous
A watch company determines that each box of 500 watches has an average of 10 defective watches with standard deviation 3. Suppose that 1000 boxes are produced. Use Chebychev′s Theorem to estimate the number of boxes having between 0 and 20 defective watches. Round the answer to the nearest integer.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
dumbcow
  • dumbcow
Chebychev′s Inequality states given standard deviation k no more than 1/k^2 of values will be more than k deviations from mean to find k we see 20 is 10 more than our mean of 10 watches 10 is 10/3 deviations k = 10/3 k^2 = 100/9 1/k^2 = 9/100 9/100 * 1000 = 90 Therefore no more than 90 boxes will have more than 20 defective watches 1000-90=910 910 boxes will have between 0 and 20 defective watches Hope this helps

Looking for something else?

Not the answer you are looking for? Search for more explanations.