anonymous
  • anonymous
25e^0.1x/e^0.1x + 3=10
Mathematics
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anonymous
  • anonymous
25e^0.1x/e^0.1x + 3=10
Mathematics
schrodinger
  • schrodinger
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
Can you type it out using the equation toolbox? This question is unclear.
anonymous
  • anonymous
Written as it, it works out to 25+3 = 10 which makes no sense.
anonymous
  • anonymous
yes, exactly.

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anonymous
  • anonymous
yes exactly u r true
anonymous
  • anonymous
dhatra aditya its seem to be that u r indian
anonymous
  • anonymous
\[25e^0.1x \div e^0.1x +3 = 10\]
anonymous
  • anonymous
\[\frac{25e^{0.1x}}{e^{0.1x}}+3=10\]Is that what you're saying?
anonymous
  • anonymous
Yes, sorry
anonymous
  • anonymous
thats the same as 25 = 7.
anonymous
  • anonymous
If what I've written is correct, there are no solutions. The statement is false.
anonymous
  • anonymous
The 3 is written in the denominator
anonymous
  • anonymous
AHHHH....
anonymous
  • anonymous
But you'd have\[\frac{25}{3}=10\]
anonymous
  • anonymous
Unless it's\[\frac{25e^{0.1x}}{e^{0.1x}+3}=10\]
anonymous
  • anonymous
Is that what you mean ^^ ?
anonymous
  • anonymous
yes, that
anonymous
  • anonymous
Okay...
anonymous
  • anonymous
Multiply both sides by\[e^{0.1x}+3\]to obtain\[25e^{0.1x}=10(e^{0.1x}+3)=10e^{0.1x}+30\]
anonymous
  • anonymous
Subtract 10e^(0.1x) from both sides to get\[15e^{0.1x}=30 \rightarrow e^{0.1x}=2\]
anonymous
  • anonymous
Now take the natural logarithm of both sides:\[\ln e^{0.1x}=\ln 2 \rightarrow 0.1x=\ln 2\]Multiply both sides by 10 to give,\[x=10\ln 2\]
anonymous
  • anonymous
hello

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