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anonymous
 5 years ago
if you simplify [(x2)/(x+2)]+[(x1)/(x+2)] all over [(x)/(x+1)][(2x3)/(x)] is the answer: 3/x+3?
anonymous
 5 years ago
if you simplify [(x2)/(x+2)]+[(x1)/(x+2)] all over [(x)/(x+1)][(2x3)/(x)] is the answer: 3/x+3?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0UGHHH instead of [(x1)/(x+2)] it is actually: [(x1)/(x+1)]

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0hmm i get something different 2x(x^22)/(x+2)(x^2x3)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay..that is why i'm asking. I got really confused. I hope the way I tried to explain what the equation looks like was not too challenging.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Could you somehow show me how you got this answer?

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0for the top part you need to combine fractions common denominator is (x+2)(x+1) you should get: [(x2)(x+1)+(x+2)(x1)]/(x+2)(x+1) In the bottom part do the same thing common denominator is x(x+1) you should get: [x^2 (2x3)(x+1)]/x(x+1) Now we are dividing by a fraction, this means multiply by reciprocal so flip the bottom fraction and multiply it by the top [(x2)(x+1)+(x+2)(x1)]/(x+2)(x+1) * x(x+1)/[x^2 (2x3)(x+1)] there is an (x+1) we can cancel then expand and add like terms x(2x^2 4)/(x+2)(x^2+x+3) you can factor out a 2 on top and pull out a negative from bottom leaving 2x(x^22)/(x+2)(x^2x3)
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