anonymous
  • anonymous
if you simplify [(x-2)/(x+2)]+[(x-1)/(x+2)] all over [(x)/(x+1)]-[(2x-3)/(x)] is the answer: -3/-x+3?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
UGHHH instead of [(x-1)/(x+2)] it is actually: [(x-1)/(x+1)]
dumbcow
  • dumbcow
hmm i get something different -2x(x^2-2)/(x+2)(x^2-x-3)
anonymous
  • anonymous
okay..that is why i'm asking. I got really confused. I hope the way I tried to explain what the equation looks like was not too challenging.

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anonymous
  • anonymous
Could you somehow show me how you got this answer?
dumbcow
  • dumbcow
for the top part you need to combine fractions common denominator is (x+2)(x+1) you should get: [(x-2)(x+1)+(x+2)(x-1)]/(x+2)(x+1) In the bottom part do the same thing common denominator is x(x+1) you should get: [x^2 -(2x-3)(x+1)]/x(x+1) Now we are dividing by a fraction, this means multiply by reciprocal so flip the bottom fraction and multiply it by the top [(x-2)(x+1)+(x+2)(x-1)]/(x+2)(x+1) * x(x+1)/[x^2 -(2x-3)(x+1)] there is an (x+1) we can cancel then expand and add like terms x(2x^2 -4)/(x+2)(-x^2+x+3) you can factor out a 2 on top and pull out a negative from bottom leaving -2x(x^2-2)/(x+2)(x^2-x-3)

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