anonymous
  • anonymous
if you simplify [(x-2)/(x+2)]+[(x-1)/(x+2)] all over [(x)/(x+1)]-[(2x-3)/(x)] is the answer: -3/-x+3?
Mathematics
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
UGHHH instead of [(x-1)/(x+2)] it is actually: [(x-1)/(x+1)]
dumbcow
  • dumbcow
hmm i get something different -2x(x^2-2)/(x+2)(x^2-x-3)
anonymous
  • anonymous
okay..that is why i'm asking. I got really confused. I hope the way I tried to explain what the equation looks like was not too challenging.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Could you somehow show me how you got this answer?
dumbcow
  • dumbcow
for the top part you need to combine fractions common denominator is (x+2)(x+1) you should get: [(x-2)(x+1)+(x+2)(x-1)]/(x+2)(x+1) In the bottom part do the same thing common denominator is x(x+1) you should get: [x^2 -(2x-3)(x+1)]/x(x+1) Now we are dividing by a fraction, this means multiply by reciprocal so flip the bottom fraction and multiply it by the top [(x-2)(x+1)+(x+2)(x-1)]/(x+2)(x+1) * x(x+1)/[x^2 -(2x-3)(x+1)] there is an (x+1) we can cancel then expand and add like terms x(2x^2 -4)/(x+2)(-x^2+x+3) you can factor out a 2 on top and pull out a negative from bottom leaving -2x(x^2-2)/(x+2)(x^2-x-3)

Looking for something else?

Not the answer you are looking for? Search for more explanations.