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anonymous
 5 years ago
Find the equation of the line perpendicular to the line containing (2, 4) with slope zero, going through (2, 4). What's the slope? I'm confused.
anonymous
 5 years ago
Find the equation of the line perpendicular to the line containing (2, 4) with slope zero, going through (2, 4). What's the slope? I'm confused.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0First line goes through (2,4) and is horizontal. Second line goes through the same point and is perpendicular (i.e. vertical). It's slope is 'infinity'.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The slope is defined as\[m=\frac{y_2y_1}{x_2x_1}\]For the horizontal line, you have that it has the same yvalue for ANY x value, so the slope is\[m=\frac{yy}{x_2x_1}=\frac{0}{x_2x_1}=0\]but

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for the second line, the vertical one, it has the same xvalue for ALL yvalues, so you end up with\[m=\lim_{x_0 \rightarrow x}\left \frac{y_2y_1}{x_0x} \right=\infty\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0because you end up dividing by zero (just put numbers into your calculator where you hold the numerator fixed and let the denominator get closer and closer to zero, and you'll see the result gets larger and larger.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0My first equation I have is y=4 which is horizontal right? How do I make my second equation to show what you are showing me?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x=2 means, "x is 2 for all y".

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh okay, this is the case because both of the points are the same, correct?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Which points are you talking about?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Both lines share only one point. The horizontal line has different x for same y. The vertical has same x for different y.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it seems it is only asking for one slope? You are getting two aren't you?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You're being asked for the slope of the line perpendicular to the line with slope zero. This perpendicular line is the vertical one, and it has the (technically undefined, and therefore nonexistent) slope of infinity.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Look at what I'm about to send.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The slope of the line is also the tan of the angle subtended between the positive xaxis and the line (i.e. tan(theta) since by definition of tan, tan is opposite over adjacent). The tan function 'blows up' as you go to theta = 90 degrees...plot it...check it out. Use wolframalpha.com or download this free software: http://www.geogebra.org/cms/

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well we have not really got that far, I appreciate your help. I understand a lot better. So basically the equation of the line is y=4? because you also have x=2 and it says THE so he is only asking for one.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0SOOO the equation of the line perpendicular is x=2 while the slope does not exist or is infinite. Right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, to your last post.
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