I wanted to know why I can't apply the alternating series test to this series sigma n=1 to infinity (-1)^n-1 sin n

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Can you make the expression clearer?

Is it,\[(-)^{n-1}\sin n\]?

\[\sum_{n=1}^{\infty}(-1)^{n-1} \sin( n )\] maybe that's what he meant?

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