anonymous
  • anonymous
find the limits when h ->0 h /tan^2h (calculus 1 style)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
I think Lokisan did this for you last night. What don't you understand?
anonymous
  • anonymous
because i need to know on the trig way what she told me i understood very clear
anonymous
  • anonymous
but i need to do it without the l'hopitals way

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anonymous
  • anonymous
and i dont know :(
anonymous
  • anonymous
\[\lim_{h \rightarrow 0}\frac{h.\cos^2h}{\sin^2h} = \frac{0}{0} = UND\] you have to use L'hopital's rule since you have 0/0 which is an undertermined form.
anonymous
  • anonymous
ok,, but the professor told me i have to trig function that can help me to define this sinh /h and cosh-1
anonymous
  • anonymous
but why make it so complicated lol? :)
anonymous
  • anonymous
mm calculus 1... i am not in cal 2... they didnt teach me the l'hopital way
anonymous
  • anonymous
:(
anonymous
  • anonymous
lol, this is calculus I too :) believe me
anonymous
  • anonymous
l'hopital is one of the first things taught in Cal I
anonymous
  • anonymous
if you understand L'hopital's rule, then you won't find difficulty solving such problems
anonymous
  • anonymous
mm.. so can u teachme de difficult way
anonymous
  • anonymous
i understand it now... but he dont want to look at that in that way
anonymous
  • anonymous
LOL, I'm afraid my profs skipped the difficult way ^_^" and I'm only aware of this way and many others too
anonymous
  • anonymous
jajaajaja,,,
anonymous
  • anonymous
lol, they skipped the cosh and sinh from our syllabus
anonymous
  • anonymous
:(....
anonymous
  • anonymous
OK, here is the other method (not necessarily recommended for this problem) h lim (h cos h)/h multiplied by lim (h cos h/h) divided by lim (h tan h)/h (htan/h)
anonymous
  • anonymous
why cosh multiplied by cosh
anonymous
  • anonymous
I am just expanding cos^2 h. You can take the lim of one cos h and multiply by another cos h
anonymous
  • anonymous
ok so, if we change h/tan^2h by h/sin^2h/cos^h
anonymous
  • anonymous
Look this has too many terms to understand this method. This method is usually done for something simple like lim (sin x). If you wanted to us that method on this simple one you multiply by x and divide by x. (You are essentially dividing by 1; it changes nothing.) You are trying to manipulate it because sin x/x =1.
anonymous
  • anonymous
ohhhhh

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