## anonymous 5 years ago find the limits when h ->0 h /tan^2h (calculus 1 style)

1. anonymous

I think Lokisan did this for you last night. What don't you understand?

2. anonymous

because i need to know on the trig way what she told me i understood very clear

3. anonymous

but i need to do it without the l'hopitals way

4. anonymous

and i dont know :(

5. anonymous

$\lim_{h \rightarrow 0}\frac{h.\cos^2h}{\sin^2h} = \frac{0}{0} = UND$ you have to use L'hopital's rule since you have 0/0 which is an undertermined form.

6. anonymous

ok,, but the professor told me i have to trig function that can help me to define this sinh /h and cosh-1

7. anonymous

but why make it so complicated lol? :)

8. anonymous

mm calculus 1... i am not in cal 2... they didnt teach me the l'hopital way

9. anonymous

:(

10. anonymous

lol, this is calculus I too :) believe me

11. anonymous

l'hopital is one of the first things taught in Cal I

12. anonymous

if you understand L'hopital's rule, then you won't find difficulty solving such problems

13. anonymous

mm.. so can u teachme de difficult way

14. anonymous

i understand it now... but he dont want to look at that in that way

15. anonymous

LOL, I'm afraid my profs skipped the difficult way ^_^" and I'm only aware of this way and many others too

16. anonymous

jajaajaja,,,

17. anonymous

lol, they skipped the cosh and sinh from our syllabus

18. anonymous

:(....

19. anonymous

OK, here is the other method (not necessarily recommended for this problem) h lim (h cos h)/h multiplied by lim (h cos h/h) divided by lim (h tan h)/h (htan/h)

20. anonymous

why cosh multiplied by cosh

21. anonymous

I am just expanding cos^2 h. You can take the lim of one cos h and multiply by another cos h

22. anonymous

ok so, if we change h/tan^2h by h/sin^2h/cos^h

23. anonymous

Look this has too many terms to understand this method. This method is usually done for something simple like lim (sin x). If you wanted to us that method on this simple one you multiply by x and divide by x. (You are essentially dividing by 1; it changes nothing.) You are trying to manipulate it because sin x/x =1.

24. anonymous

ohhhhh

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