anonymous
  • anonymous
find two consecutive negative odd integers such that the square of the lesser integer is 40 more than the square of the greater integer
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
9 ,11. sounds weird :P
anonymous
  • anonymous
nop
anonymous
  • anonymous
i mean-9,-11

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anonymous
  • anonymous
how did you get that?
anonymous
  • anonymous
it amounts to 81 and 121
anonymous
  • anonymous
i think se said consecutive
anonymous
  • anonymous
wait im sorry buit i dont understand like how you would do that prblem now..ciykd someone explain that? thanks
anonymous
  • anonymous
ok for for a general formula try -x^2 =(-x+2)^2 + 40
anonymous
  • anonymous
but then dont the x's cancel out?
anonymous
  • anonymous
ok
anonymous
  • anonymous
u start with -x^2=(-x+2)^2+40 multiply the square ull get -x^2=x^2-4x+4
anonymous
  • anonymous
sorry -x^2=x^2-4x+4+40
anonymous
  • anonymous
oh ok thank you guys!!
anonymous
  • anonymous
wait where does the 4x come from?

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