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anonymous
 5 years ago
find two consecutive negative odd integers such that the square of the lesser integer is 40 more than the square of the greater integer
anonymous
 5 years ago
find two consecutive negative odd integers such that the square of the lesser integer is 40 more than the square of the greater integer

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.09 ,11. sounds weird :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did you get that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it amounts to 81 and 121

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think se said consecutive

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait im sorry buit i dont understand like how you would do that prblem now..ciykd someone explain that? thanks

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok for for a general formula try x^2 =(x+2)^2 + 40

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but then dont the x's cancel out?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u start with x^2=(x+2)^2+40 multiply the square ull get x^2=x^24x+4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry x^2=x^24x+4+40

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh ok thank you guys!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait where does the 4x come from?
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