anonymous
  • anonymous
(a + 1 - 6/a) / (a - 1 - 2/a) simplify
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
lol...isnt it a^2+a-6/a^2-a-2
anonymous
  • anonymous
\[\frac{1-\frac{6}{a}+a}{-1-\frac{2}{a}+a} \] Is this the problem expression?
anonymous
  • anonymous
yes only with terms rearranged

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anonymous
  • anonymous
Combine the terms in the Numerator and the Denominator into one fraction respectively. \[\frac{\frac{-6+a+a^2}{a}}{\frac{-2-a+a^2}{a}} \] Invert the denominator and multiply the result by the Numerator. \[\frac{-6+a+a^2}{-2-a+a^2} \] Both the Numerator and Denominator can be factored. \[\frac{((-2+a) (3+a))}{((-2+a) (1+a))} \]\[\frac{3+a}{1+a} \] Using Mathematica for the symbol manipulation and that is why the term ordering does't look right.
anonymous
  • anonymous
ok out casgirl
anonymous
  • anonymous
outcastgirl

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