describe the relationship between the graphs of the linear equation y=1/3x+10 and 3y=9x+2
Stacey Warren - Expert brainly.com
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did you type the question wrong?
it looks like it's going for a perpendicular relationship, but that would be a negative reciprocal
if not, the second line is 9 times as steep (slope wise) as the first...
and they would intercept at
1/3x + 10 = 3x + 2/3
x + 30 = 9x + 2
-8x = -28
x = 7/2
y = 335 / 30 = 67 / 6
intersect at (7/2, 67/6)
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it sounds like you know what you are doing though! lol
lols then i was right in the first sentence.
ignore the rest
i am just not sure how to solve the equation...how do i start?
the definition of perpendicular lines requires that the slopes of the lines have to be negative reciprocals. Negative reciprocals means that it's negative and inversed (1/x)
so in your example
y=1/3x+10 and 3y=9x+2
change both to y = mb + c
so the slopes are -1/3 and 3
if you take the negative reciprocal of -1/3 would be
which would equal 3
Since they are negative reciprocals, they are perpendicular
it's a rule
just like how parallel lines have the same slope, it's the same idea
perpendicular lines are negative reciprocals