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anonymous

  • 5 years ago

x/2y-y/2x --------- 2/y+2/x

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  1. amistre64
    • 5 years ago
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    looks like someones trying to get there homework/test done ;)

  2. amistre64
    • 5 years ago
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    how you like the new openstudy sstar?

  3. amistre64
    • 5 years ago
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    multiply top and bottom by 2xy right? x^2-y^2 --------- 4x+4y

  4. anonymous
    • 5 years ago
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    \[\frac{\frac{x}{2y}- \frac{y}{2x}}{\frac{2}{y}+\frac{2}{x}} \]\[= \frac{x^2-y^2}{2yx}.\frac{xy}{2x+2y} = \frac{xy(x-y)(x+y)}{4yx(x+y)} = \frac{(x-y)}{4}\] Correct me if I'm wrong ^_^

  5. anonymous
    • 5 years ago
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    I like it very much amistre ^_^, it's very nice!

  6. amistre64
    • 5 years ago
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    divide by your favorite way of dividing...long hand prolly x/4 -y/4 ----------------- 4x +4y | x^2 -y^2 -x^2 -xy ----------- -xy -y^2 xy + y^2 ---------- 0 x/4 - y/4 = (x-y)/4 yor right :)

  7. anonymous
    • 5 years ago
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    awesome ^_^~

  8. amistre64
    • 5 years ago
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    i think you get a medal for it ;)

  9. anonymous
    • 5 years ago
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    thank you all so much this really helped!!

  10. anonymous
    • 5 years ago
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    most welcome :)

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spraguer (Moderator)
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