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anonymous
 5 years ago
last year you could get a hamburger,fries, and coloa for $2.70. since the price of hamburger increased 20%, the prices of fries has increased 10%, and cola 60%. The same meal now costs 3.46$ if the price of a cola is now 20 cents more than that of a hamburger, what was the price of each item last year?
anonymous
 5 years ago
last year you could get a hamburger,fries, and coloa for $2.70. since the price of hamburger increased 20%, the prices of fries has increased 10%, and cola 60%. The same meal now costs 3.46$ if the price of a cola is now 20 cents more than that of a hamburger, what was the price of each item last year?

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0c = h+.20 h + c + f = 2.70 (then) h(.2) + c(.6) + f(.1) = 3.46 (now)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so for then its would be 20 cents 60 cents 10 cents?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0dont know yet :) im thinknig I should figure the percentage of the price as well....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0if we test out that they all cost .30 then; we can see where our guess leads us...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0.30(3) = 2.70 so that much would be good; .3(.2) + .3(.6) + .3(.1) .06 +.18 +.03 = .27 is not right, so we are missing something; we went lower in price instead of higher... they should be. the percentages should be add to 1 to account for the base price and the rise in percentage...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0h(1.2) + c(1.6) + f(1.1) = 3.46 is more accurate equation..

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0at .30 cents then we would get: .36 +.48 +.33 = .36 + .81 = 1.17 is better; given that my .30 was off to begin with; shoulda been .90 :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0h(1.2) = c(1.6)  .20 : is good for this the total price increased by .76. 76/270 = percent changed. which is an awful decimal so we will keep it as a fraction to make it easier on us. ................................................ h(1.2) + c(1.6) + f(1.1) = 2.70(3.46/2.70) (c(1.6)  .20)(1.2) + c(1.6) + f(1.1) = 3.46 c(1.92)  .24 + c(1.6) + f(1.1) = 3.46 c(3.52) + f(1.1)=3.70 is what I get so far...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0h(1.2) + c(1.6) + f(1.1) = 2.70(3.46/2.70) c(1.6)  .20 + c(1.6) + f(1.1) = 3.46 < corrected for my stupidity :) c(3.2) + f(1.1) = 3.70 is what we are looking at; not that it helps me much at the moment :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0ack!!..... c(3.2) + f(1.1) = 3.66 ...and thats should be right lol... we really need someone smarter then me on this ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol thanks for all your help ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so just so were absolutely clear..lol... soda is $3.20 fries are 1.10 and burger is 1.20?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0f = 2.70  h  c; if re can get f in terms of c this would be delightful... f(1.1) = (3.46 h(1.2)  c(1.6)) f = [3.46 h(1.2)  c(1.6)]/1.1 h = [c(1.6)  .20]/1.2 now we can test this theory of mine out and see where it ends up ;) we got everything in terms of "c" c + h + f = 2.70 c + [c(1.6)  .20]/1.2 + [3.46 {[c(1.6)  .20]/1.2}(1.2)  c(1.6)]/1.1 = 2.70 the equation editor should be able to clean that up for us: \[c + \frac{[c(1.6)  .20]}{1.2} + \frac{[3.66 c(3.2)]}{1.1} = 2.70\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0get common denominators: (1.2)(1.1) c(1.32) +(1.1)[c(1.6)  .20] + (1.2)[3.66 c(3.2)] = 2.70(1.32) c(1.32) + c(1.76)  .22 + 4.392  c(3.84) = 3.564 c(1.32 + 1.76  3.84) = 3.564 +.22 4.392

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0c(.76) = .608 c = .80 cents.... with alot of luck ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lets get some confidence and try to work out the rest :) c(1.6) = price of cola today .8(1.6) = 1.28 h(1.2) = 1.28  .20 = 1.18 is the cost of a hamburger today. f(1.1) = 3.46  1.18  1.28 f(1.1) = cost of fries today = 1.00 corssing fingers and typing is not a good combination :) but im almost there lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0f = 1/1.1 = 0.9090909090909091 = .91 h = 1.18/1.2 = 0.9833333333333333 = .98, or .99 c = 1.28/1.6 = .80 lets add them and see if we are close :) .80 + .91 + .98 = 2.70 2.69 = 2.70 ; so Id go with h= .99

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0h = .99; c=.80; f=.91 last year
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