anonymous
  • anonymous
last year you could get a hamburger,fries, and coloa for $2.70. since the price of hamburger increased 20%, the prices of fries has increased 10%, and cola 60%. The same meal now costs 3.46$ if the price of a cola is now 20 cents more than that of a hamburger, what was the price of each item last year?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
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amistre64
  • amistre64
c = h+.20 h + c + f = 2.70 (then) h(.2) + c(.6) + f(.1) = 3.46 (now)
anonymous
  • anonymous
so for then its would be 20 cents 60 cents 10 cents?
amistre64
  • amistre64
dont know yet :) im thinknig I should figure the percentage of the price as well....

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amistre64
  • amistre64
if we test out that they all cost .30 then; we can see where our guess leads us...
amistre64
  • amistre64
.30(3) = 2.70 so that much would be good; .3(.2) + .3(.6) + .3(.1) .06 +.18 +.03 = .27 is not right, so we are missing something; we went lower in price instead of higher... they should be. the percentages should be add to 1 to account for the base price and the rise in percentage...
amistre64
  • amistre64
h(1.2) + c(1.6) + f(1.1) = 3.46 is more accurate equation..
amistre64
  • amistre64
at .30 cents then we would get: .36 +.48 +.33 = .36 + .81 = 1.17 is better; given that my .30 was off to begin with; shoulda been .90 :)
amistre64
  • amistre64
h(1.2) = c(1.6) - .20 : is good for this the total price increased by .76. 76/270 = percent changed. which is an awful decimal so we will keep it as a fraction to make it easier on us. ................................................ h(1.2) + c(1.6) + f(1.1) = 2.70(3.46/2.70) (c(1.6) - .20)(1.2) + c(1.6) + f(1.1) = 3.46 c(1.92) - .24 + c(1.6) + f(1.1) = 3.46 c(3.52) + f(1.1)=3.70 is what I get so far...
amistre64
  • amistre64
h(1.2) + c(1.6) + f(1.1) = 2.70(3.46/2.70) c(1.6) - .20 + c(1.6) + f(1.1) = 3.46 <-- corrected for my stupidity :) c(3.2) + f(1.1) = 3.70 is what we are looking at; not that it helps me much at the moment :)
amistre64
  • amistre64
ack!!..... c(3.2) + f(1.1) = 3.66 ...and thats should be right lol... we really need someone smarter then me on this ;)
anonymous
  • anonymous
lol thanks for all your help ;)
anonymous
  • anonymous
so just so were absolutely clear..lol... soda is $3.20 fries are 1.10 and burger is 1.20?
amistre64
  • amistre64
f = 2.70 - h - c; if re can get f in terms of c this would be delightful... f(1.1) = (3.46 -h(1.2) - c(1.6)) f = [3.46 -h(1.2) - c(1.6)]/1.1 h = [c(1.6) - .20]/1.2 now we can test this theory of mine out and see where it ends up ;) we got everything in terms of "c" c + h + f = 2.70 c + [c(1.6) - .20]/1.2 + [3.46 -{[c(1.6) - .20]/1.2}(1.2) - c(1.6)]/1.1 = 2.70 the equation editor should be able to clean that up for us: \[c + \frac{[c(1.6) - .20]}{1.2} + \frac{[3.66 -c(3.2)]}{1.1} = 2.70\]
amistre64
  • amistre64
get common denominators: (1.2)(1.1) c(1.32) +(1.1)[c(1.6) - .20] + (1.2)[3.66 -c(3.2)] = 2.70(1.32) c(1.32) + c(1.76) - .22 + 4.392 - c(3.84) = 3.564 c(1.32 + 1.76 - 3.84) = 3.564 +.22 -4.392
amistre64
  • amistre64
c(-.76) = -.608 c = .80 cents.... with alot of luck ;)
amistre64
  • amistre64
lets get some confidence and try to work out the rest :) c(1.6) = price of cola today .8(1.6) = 1.28 h(1.2) = 1.28 - .20 = 1.18 is the cost of a hamburger today. f(1.1) = 3.46 - 1.18 - 1.28 f(1.1) = cost of fries today = 1.00 corssing fingers and typing is not a good combination :) but im almost there lol
amistre64
  • amistre64
f = 1/1.1 = 0.9090909090909091 = .91 h = 1.18/1.2 = 0.9833333333333333 = .98, or .99 c = 1.28/1.6 = .80 lets add them and see if we are close :) .80 + .91 + .98 = 2.70 2.69 = 2.70 ; so Id go with h= .99
amistre64
  • amistre64
h = .99; c=.80; f=.91 last year

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