anonymous 5 years ago can anyone help me get started on this? dh/dt= 0.016(2.5-h) Solve the differential equation to find h in terms of t.

1. anonymous

Integrate both side, you get: $h(t)=\int\limits_{}^{}0.016(2.5-h)dh$

2. anonymous

Can you do the integration?

3. anonymous

h(t)= 0.04t-0.016h^2 ?

4. anonymous

Almost there. The second term should be over 2, and don't forget to add a constant (+c).

5. anonymous

!!! Rookie mistakes!!! Yes it should. h(t)=0.04t-((0.016h^2)/2)+c Thankyou AnwarA

6. anonymous

We all do that kind of mistakes. You're welcome :)