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anonymous
 5 years ago
Graph the circle (x^2)+(y^2)8x+6y+21=0
anonymous
 5 years ago
Graph the circle (x^2)+(y^2)8x+6y+21=0

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok.. How are you with completing squares?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=graph+%28x^2%29%2B%28y^2%298x%2B6y%2B21%3D0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0To graph it by hand, however, you would need to complete the squares... Look at the variables to the first power, like x and y, and use the constants to help you complete the square.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0add numbers to both sides of the equations as you do it, so that you can balancing it out. The end result would be like (xa)^2 + (yb)^2 = r^2, where r is the radios, and (a,b) is the center of the circle.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Im not that good with completing squares. I don't remember the process

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well.. You need to divide the constant by 2, and then square that. So if the equation is like x^2  8x, you divide the first power x by 2, to get 4, and then you square that number, which will give you 16. Add 16 to both sides of the equation. and you will get x^2 8x +16 = 16. You now can complete the square on the left side, which will be (x4)^2 = 16.
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