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anonymous

  • 5 years ago

(y^2)+2y-2x-7=0

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  1. anonymous
    • 5 years ago
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    y^2+2y= 2x+7 (y^2+2y+1)-1=2x+7 (y+1)^2=2x+8 (y+1)^2=2(x+4) which is a right handed parabola

  2. anonymous
    • 5 years ago
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    is that u were looking for?

  3. anonymous
    • 5 years ago
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    She has posted so many questions about graphing I don't even know what is the question anymore.

  4. anonymous
    • 5 years ago
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    im just not sure how to find the points for them

  5. anonymous
    • 5 years ago
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    okay...lets try to draw it.....the above equation can be written as below (y-(1))^2=2(x-(-4)). which means its centre is (-4,-1). can u locate this point now?

  6. anonymous
    • 5 years ago
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    yeah. i just dont know how to find it myself if that makes sense well here i have another one for practice, can you go through this one with me..... (y^2)+8y-2x+22=0

  7. anonymous
    • 5 years ago
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    check this one out

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  8. anonymous
    • 5 years ago
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    This is what I would do... switch the x and y, so that (x^2)+8x-2y+22=0, and also flip the x and y axis. So that you are essentially graphing a parabola, which is easy, and then flip the page back to normal, and you get the equation you want.

  9. anonymous
    • 5 years ago
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    did u see that?

  10. anonymous
    • 5 years ago
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    too much flipping....:D

  11. anonymous
    • 5 years ago
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    ahh im so confused ha

  12. anonymous
    • 5 years ago
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    which part r u confused of?

  13. anonymous
    • 5 years ago
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    how to get the point and how to determine the height or width of it

  14. anonymous
    • 5 years ago
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    i mean i know how to get the vertex but I dont know how to figure out how much it opens up

  15. anonymous
    • 5 years ago
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    okay..for that put x=0 that will give u the point where it touches the y axis and vice versa...got it?

  16. anonymous
    • 5 years ago
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    do you mean to put x=0 when its like this y=1/2x^2=4x=11 ?

  17. anonymous
    • 5 years ago
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    (y+1)^2=2(x+4) is our parabola. lets put x=0 , we get (y+1)^2=2(0+4) or (y+1)^2=8 or y^2+2y-7=0 which is quadratic , solving it will give us two values of y which will give us two points where the parabola intersects the y-axis.. alright?

  18. anonymous
    • 5 years ago
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    thank you

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